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siniylev [52]
3 years ago
15

Complete the statement below by naming the second triangle in the correct order, and

Mathematics
1 answer:
Eduardwww [97]3 years ago
4 0

Answer:

hermoso chica mala vibraciones

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Yesterday morning, at 6:00 AM, water started leaking from a tank at a constant rate. The tank contained8,496liters of water at 6
GREYUIT [131]

A linear equation can be written as:

y = a*x + b

where a is the slope and b is the y-intercept.

If we know that the line passes through the points (x₁, y₁) and (x₂, y₂) the slope is:

a = \frac{y_2 - y_1}{x_2 - x_1}

The answers are:

a) y = (-12 L/min)*t + 9,000 L

b) 6,840 L

a) Here we know that we can model this situation with a linear equation, we know that the leak starts at 6:00 am, then we define t = 0 as 6:00 am

We know that at 6:42 am  (at t = 42 mins) the tank has 8,496 liters.

And at 7:15 am (at t = 75 mins) the tank has 8,100 liters.

Then we have two points of the line:

(42 mins, 8,496 liters)

(75 mins, 8,100 liters)

Then the slope is:

a = \frac{8,100 liters - 8,496 liters }{75 mins -42 mins } = -12 L/min

So the line will be something like:

y = (-12 L/min)*t + b

To find the value of b, which is the initial volume of water in the tank, we use the point (75 mins, 8,100 liters)

This means that if t = 75 mins, then we have y = 8,100 L

So we can replace these two on the above equation:

8,100 L = (-12 L/min)*75 mins + b

8,100L = -900L + b

8,100L + 900L = b = 9,000 L

Then the linear equation is:

y = (-12 L/min)*t + 9,000 L

b) Now we want to know how much water is in the tank at 9:00 am.

Notice that 9:00 am is 3 hours after 6:00 am, our t = 0.

Then  9:00am is equivalent to t = 180 mins.

So to know the volume of water that there is in the tank at 9:00 am, we just need to evaluate the linear function at t = 180 mins.

y = (-12 L/min)*180 mins + 9,000 L = 6,840 L

If you want to learn more, you can read:

brainly.com/question/24594539

7 0
2 years ago
A student's grade for the four quarters are 95, 83, 91, and 85. What does the student need to earn on the final exam to have an
gulaghasi [49]

Answer:

The least score the student can get is 71 to get an overall B average at the end of the year.

Step-by-step explanation:

Let the score she needs to get be = x

We now have to take the mean of all the five subjects <em>(including x)</em> and equate it to the least score she can have to get a B grade.

Let us take the least score the student needs to get a B grade to be 85

Mean of all 5 scores =

\frac{95+83+91+85+x}{5}=85

\frac{354+x}{5} =85

354+x = 425

x = 71

The least score the student can get is 71 to get an overall B average at the end of the year.

3 0
3 years ago
In a laboratory, under favorable conditions, a bacteria grows at an exponential rate. the number of cells C in the population is
Naily [24]
Selection C is appropriate.

_____
A. The population is constant at 8.

B. The population is constant at 24.

C. Matches the problem description.

D. The initial population is 24 and after 1 hour is 72.
4 0
3 years ago
Read 2 more answers
Help plz its math and i will give brainlest if u answer
lesantik [10]

Answer:

not a right triangle

Step-by-step explanation:

We can use the Pythagorean theorem to see if it is a right triangle

a^2 + b^2 = c^2

15^2 + 12^2 = 21^2

225 + 144 = 441

369 = 441

This is not true so it is not a right triangle

3 0
3 years ago
Read 2 more answers
It is thought that not as many Americans buy presents to celebrate Valentine's Day anymore. A random sample of 40 Americans yiel
evablogger [386]

Answer:

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

 (0.3672 , 0.7328)

Step-by-step explanation:

<u><em>Explanation:</em></u>-

Given Random sample size n =40

Sample proportion

                            p = \frac{x}{n} = \frac{22}{40} = 0.55

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

   

          (p-Z_{\alpha } \sqrt{\frac{pq}{n} } , p + Z_{\alpha } \sqrt{\frac{pq}{n} } )

         

The Z-value Z₀.₉₈ = Z₀.₀₂ = 2.326

98% confidence interval of the true proportion of all Americans who celebrate Valentine's Day

    (0.55-2.326\sqrt{\frac{0.55 X0.45}{40} } , 0.55 + 2.326\sqrt{\frac{0.55 X0.45}{40} } )

  ( 0.55 - 0.1828 , 0.55 + 0.1828)

  (0.3672 , 0.7328)

         

6 0
3 years ago
Read 2 more answers
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