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miv72 [106K]
3 years ago
7

Two daises cost $1.50 how much would 7 cost

Mathematics
2 answers:
Basile [38]3 years ago
8 0
If 2 daisies are $1.50, that means each individual daisy is $0.75. So, 7 daisies would cost $5.25. :))))
Ira Lisetskai [31]3 years ago
8 0
Hey there!

If two daisies cost $1.50, you would divide this by 2 to find the cost per daisy. $1.50 divided by 2 is 0.75, meaning that each daisy costs $0.75. 

Now, we can multiply this unit price by 7 to find the total cost for 7 daisies. You can do this by multiplying $0.75 by 7 to get 5.25. $5.25 will be the total cost for 7 daisies. 

Hope this helped you out! :-)
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For which rational expressions is –5 an excluded value? Check all that apply.
Anika [276]

Answer:

option C and F

Step-by-step explanation:

Given excluded value is x=-5

Excluded value are the values that makes the denominator 0

Now we check out each option and see , in which option the denominator becomes 0 when x=-5

When denominator has (x+5) then when we plug in x=-5

(x+5) becomes (-5+5) =0

So we look at the options that has factor (x+5) in the denominator

In option C  we have x^2 -25

When we plug in -5  for x  then it becomes (-5)^2 - 25 =0

So x=-5  makes the denominator 0

-5 is an excluded value for option C

Last option f has x+5 in the denominator

x=-5 make the denominator 0

so , -5 is an excluded value for option F


3 0
3 years ago
Which equation is a function?
-Dominant- [34]

the answer is B -- no matter the x factor y should be single

3 0
4 years ago
Plz help quick! I’m being timed
Kisachek [45]

Answer:

14 cents per oz

Step-by-step explanation:

399/28.5=14

Hope this helps!

6 0
4 years ago
Solve for all possible values of x : |x-3|+4=1
Advocard [28]

Answer:

D: no real solutions

Step-by-step explanation:

7 0
3 years ago
Consider the polynomials p(x) = 3x + 27x^2 and q(x)= 2 . Find the x -coordinate(s) of the point(s) of intersection of these two
Tom [10]

Answer:

The x -coordinate(s) of the point(s) of intersection of these two polynomials are x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333

The sum of these x -coordinates is \frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}

Step-by-step explanation:

The intersections of the two polynomials, p(x) and q(x), are the roots of the equation p(x) = q(x).

Thus, 3x + 27x^2=2 and we solve for x

3x+27x^2-2=2-2\\27x^2+3x-2=0\\\left(27x^2-6x\right)+\left(9x-2\right)\\3x\left(9x-2\right)+\left(9x-2\right)\\\left(9x-2\right)\left(3x+1\right)=0

Using Zero Factor Theorem: = 0 if and only if = 0 or = 0

9x-2=0\\9x=2\\x=\frac{2}{9}

3x+1=0\\3x=-1\\x=-\frac{1}{3}

The solutions are:

x=\frac{2}{9}\approx0.2222,\:x=-\frac{1}{3}\approx-0.3333

The sum of these x -coordinates is

\frac{2}{9}+\left(-\frac{1}{3}\right)=-\frac{1}{9}

We can check our work with the graph of the two polynomials.

4 0
4 years ago
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