A parabola with the equation y=a(x-b)^2+c has a minimum of (-2,1) and a y-intercept of 5. What are the values of a, b and c? Wha

Question

Nikolay [14]

3 years ago

10

A parabola with the equation y=a(x-b)^2+c has a minimum of (-2,1) and a y-intercept of 5. What are the values of a, b and c? Wha

t are the x-intercepts?

Mathematics

1 answer:

Illusion [34] · Answer 1 · 2022-10-16T22:33:33+03:00

Illusion [34]3 years ago

5 0

Answer: 3^15

Step-by-step explanation: carry the one to the 5 divide by the third and multiply the fractions , find the mean ( average ) of the mode and square that to find your a b and c values