Question

A can of soup is in the shape of a cylinder. The diameter of the can is 8 centimeters, and the height is 10 centimeters. What is the surface area of the can, rounded to the nearest hundredth square centimeter? (Use 3.14 for π.) 351.68 cm 2 251.2 cm 2 502.4 cm 2 100.48 cm 2

Answer 1

Answer:

The surface area of the can is $351.68\ cm^{2}$

Step-by-step explanation:

we know that

The surface area of a cylinder (can of soup) is equal to

$SA=2\pi r^{2}+\pi Dh$

we have

$r=8/2=4\ cm$ ----> the radius is half the diameter

$D=8\ cm$

$h=10\ cm$

substitute the values

$SA=2(3.14)(4^{2})+(3.14)(8)(10)$

$SA=100.48+251.2=351.68\ cm^{2}$