20 POINTS PLEASE HELP DUE NEXT PERIOD

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

3 0

Given: y=x^3 and y=343
So, 343=x^3
Cube root both sides which will get rid of the cube on the right side of the equation
You are left with the cube root of 343. Which equals 7.
7*7*7=343
X=7

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$\sqrt{(x-2)^2}= \sqrt{12} \\(x-2) = \pm\sqrt{12} \\x = \pm\sqrt{12} +2\\x = \sqrt{12}+2 \,\,and\,\,x=-\sqrt{12}+2\\x= 3.46+2 \,\,and\,\,x=-3.46+2\\x =5.46\,\,and\,\,x=-1.46$