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aksik [14]
3 years ago
15

Help please, Which expression does not belong? Explain your reasoning.

Mathematics
1 answer:
ZanzabumX [31]3 years ago
4 0

Answer:

My best answer is option number 4.

Step-by-step explanation:

Because the first 3 answers follow a specific pattern in addition and division, i.e. they only go up to 4 different numbers, whereas with the 4th option, that changes. Not only that, but if you look closely, the 4th option adds 6 to itself 5 times, that's the same as 6x5, which equals 30, so if you divide 30 by 5, its almost pointless seeing as how you already know it's gonna get you 6.

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The width of a rectangular painting is 5 inches shorter than it's length. Creat a table of values to include possible widths,len
Misha Larkins [42]
A = L * W
W = L - 5

                                these are in inches...
               length                width                 area
                  10                      5                       50 in^2
                  9                        4                       36   "
                  8                        3                       24   "
                  7                        2                       14   "
                  6                        1                        6    "
                 
6 0
4 years ago
The slope of the line going through the points 2,6 and -1,-3
Verizon [17]
Answer: 3
hope that helps!

8 0
3 years ago
Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.
Vera_Pavlovna [14]

Split up the integration interval into 4 subintervals:

\left[0,\dfrac\pi8\right],\left[\dfrac\pi8,\dfrac\pi4\right],\left[\dfrac\pi4,\dfrac{3\pi}8\right],\left[\dfrac{3\pi}8,\dfrac\pi2\right]

The left and right endpoints of the i-th subinterval, respectively, are

\ell_i=\dfrac{i-1}4\left(\dfrac\pi2-0\right)=\dfrac{(i-1)\pi}8

r_i=\dfrac i4\left(\dfrac\pi2-0\right)=\dfrac{i\pi}8

for 1\le i\le4, and the respective midpoints are

m_i=\dfrac{\ell_i+r_i}2=\dfrac{(2i-1)\pi}8

  • Trapezoidal rule

We approximate the (signed) area under the curve over each subinterval by

T_i=\dfrac{f(\ell_i)+f(r_i)}2(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4T_i\approx\boxed{3.038078}

  • Midpoint rule

We approximate the area for each subinterval by

M_i=f(m_i)(\ell_i-r_i)

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4M_i\approx\boxed{2.981137}

  • Simpson's rule

We first interpolate the integrand over each subinterval by a quadratic polynomial p_i(x), where

p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}

so that

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx

It so happens that the integral of p_i(x) reduces nicely to the form you're probably more familiar with,

S_i=\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{r_i-\ell_i}6(f(\ell_i)+4f(m_i)+f(r_i))

Then the integral is approximately

\displaystyle\int_0^{\pi/2}\frac3{1+\cos x}\,\mathrm dx\approx\sum_{i=1}^4S_i\approx\boxed{3.000117}

Compare these to the actual value of the integral, 3. I've included plots of the approximations below.

3 0
3 years ago
The ratio of a to b is 2:3, and the ratio of a to c is 3: 10. What is the ratio of b to c?
Stolb23 [73]

Answer: 3:10

Step-by-step explanation:

From the question, b= 3; c=10

Ratio of b:c will be

the value of b:value of c

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4 0
3 years ago
Read 2 more answers
300 x 400 = 1200 the same as 3 x 4 = 12
ELEN [110]

Answer:

3x4=12 is 300x400=1200 but it is not multiplied by 100

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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