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sammy [17]
2 years ago
10

The probability that a student has a Visa card (event V) is .76. The probability that a student has a Master card (event M) is .

16. The probability that a student had both is .04.
Mathematics
1 answer:
Rufina [12.5K]2 years ago
8 0

Answer:

The Probability of both happening is <u>0.304</u>.

Step-by-step explanation:

P(A) × P(B)

=  0.76 × 0.4

=  <u>0.304</u>

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Which of the following expressions are equivalent to 6.53 - (-4.11) + 7.926.53?
umka21 [38]

Answer:

Choice B and Choise C.

Step-by-step explanation:

Equivalent expressions are those expressions that have the same value but they look different.

Given the following expression provided in the exercise:

6.53 - (-4.11) + 7.92

You need to remember the multiplication of signs in order to find the equivalent expressions:

(+)(+)=+\\(-)(-)=+\\(-)(+)=-\\(+)(-)=-

Then:

- Eliminating the parentheses, you get this equivalent expression:

6.53 +4.11 + 7.92

- Since the mulplication of two negative signs gives yous a positive sign, you can rewrite the original expression in this form:

-(-6.53)+4.11-(-7.92)

This is an equivalent expression to 6.53 - (-4.11) + 7.92

8 0
3 years ago
How do I solve this?? I can’t remember
Alika [10]

Answer:

Item or service cost times sales tax  so $45x0.6= meal and then you add 20% of 27

6 0
3 years ago
Consider a series system composed of 4 separate components where each component has a 30% chance of failing. Assume each compone
Marina86 [1]

Answer:

16.15% probability that exactly 3 of them would function

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of each system working:

4 components, which means that n = 4

Each has a 30% probability of failing, so p = 1 - 0.3 = 0.7

For the system to work, all 4 components have to work. This is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{4,4}.(0.7)^{4}.(0.3)^{0} = 0.2401

0.2401 probability of a system working.

If you have 7 of these systems, what is the probability that exactly 3 of them would function?

Now 7 systems, so n = 7

0.2401 probability of a system working.

We have to find P(X = 3).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{7,3}.(0.2401)^{3}.(0.7599)^{4} = 0.1615

16.15% probability that exactly 3 of them would function

5 0
3 years ago
Which set of numerical values represents the minimum, lower quartile, median, upper quartile, and maximum, in that order, of the
Nana76 [90]
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How to solve? What are the rules in BODMAS
leva [86]

Answer:

18/35

Step-by-step explanation:

1 1/5 ÷ 2  1/3

Change from mixed numbers to improper fractions

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2 1/3 = (3*2+1)/3 = 7/3

6/5÷ 7/3

Copy dot flip

6/5* 3/7

18/35

8 0
3 years ago
Read 2 more answers
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