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2 years ago

11

What is the formula of a parallelogram that is 1 2/5 tall and 7 3/4s wide. Please help. Can i just straighten into a rectangle a

nd solve?

1 answer:

sertanlavr [38]2 years ago

3 0

You can just solve for area like you do a rectangle: length x width

1 2/5 x 7 3/4=
10 17/20 or 10.85

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Consider this cube with a volume of 64 cubic centimeters.

Eduardwww [97]

Answer:

This is a perfect cube.

The side length is 4.

Taking the cube root of the volume will determine the side length.

Step-by-step explanation:

We are told that:

A cube has volume 64 centimeters cubed.

The formula for the volume of a cube = s³

Where s = side length

Hence

64 cm³ = s³

We can find s by finding the cube root of both sides

Hence,

cube root(64) = cube root(s³)

s = 4 cm

Note that 64 is a perfect cube because 4 × 4 × 4 = 4³ = 64 cm³

Therefore, it can be concluded of the cube that:

This is a perfect cube.

The side length is 4.

Taking the cube root of the volume will determine the side length.

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2 years ago

What is an equation for "five more than the product of 7 and a number t?"

fiasKO [112]

the answer is 5+(7t)

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2 years ago

The perimeter of equilateral triangle ABC is 81/3 centimeters, find the length of the radius and apothem.

MAXImum [283]

There is a typo error, the perimeter of equilateral triangle ABC is 81/√3 centimeters.

Answer:

Radius = OB= 27 cm

Apothem = 13.5 cm

A diagram is attached for reference.

Step-by-step explanation:

Given,

The perimeter of equilateral triangle ABC is 81/√3 centimeters.

Substituting this in the formula of perimeter of equilateral triangle = $3\times\ side$

$3\times\ side$ $=[tex]81\sqrt{3}$

$Side = \frac{81\sqrt{3} }{3} =27\sqrt{3} \ cm$

Thus from the diagram , Side $AB=BC=AC= 27\sqrt{3} \ cm$

We know each angle of an equilateral triangle is 60°.

From the diagram, OB is an angle bisector.

Thus $\angle OBC = 30$ °

Apothem is the line segment from the mid point of any side to the center the equilateral triangle.

Therefore considering ΔOBE, and applying tan function.

$tan\theta =\frac{perpendicular}{base} \\tan\theta=\frac{OE}{BE} \\tan\theta=\frac{OE}{\frac{27\sqrt{3}}{2} } \\tan30\times {\frac{27\sqrt{3} }{2} }= OE\\\frac{1}{\sqrt{3} } \times\frac{27\sqrt{3} }{2} =OE\\$

Thus ,apothem OE= 13.5 cm

Now for radius,

We consider ΔOBE

$cos\theta=\frac{base}{hypotenuse} \\cos30= \frac{BE}{OB} \\Cos30 = \frac{\frac{27\sqrt{3} }{2}}{OB} \\OB= \frac{\frac{27\sqrt{3} }{2}}{cos30} \\OB= \frac{\frac{27\sqrt{3} }{2}}{\frac{\sqrt{3} }{2} } \\OB =27 \ cm$

Thus for

Perimeter of equilateral triangle ABC is 81/√3 centimeters,

The radius of equilateral triangle ABC is 27 cm

The apothem of equilateral triangle ABC is 13.5 cm

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Klio2033 [76]

Answer:

Nonproportional

Step-by-step explanation:

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