Answer:
yes the sides of a triangle can have all those sides
Answer:
∫
= 
Step-by-step explanation:
To find:
∫
Solution:
Method of substitution:
Let 
Differentiate both sides with respect to 

[use
]
So,
∫
= ∫
=
where
is a variable.
(Use ∫
)
Put 
∫
= 
Use 
So,
∫
= 
where 
Without using substitution:
∫
= ∫
= 
So, same answer is obtained in both the cases.
Answer:
First then second answer below
Step-by-step explanation:
-x+y 4
-1/-1=1 x=1 y=1
y/1=1/1+4/1
y=1x+4
-x+7y 21
-1/-1=1
7y/7=1/7+21/7
y=1/7x+3
Answer:
sin²x
Step-by-step explanation:
we have
(1 − cos x)(1 + cos x)=1-cos²x
Remember that
sin²x+cos²x=1 ------> i-cos²x=sin²x
therefore
(1 − cos x)(1 + cos x)=sin²x
Answer:
x = - 10 ± 
Step-by-step explanation:
y = (x + 10)² , or
(x + 10)² = y ( take square root of both sides )
x + 10 = ±
( subtract 10 from both sides )
x = - 10 ± 