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3 years ago

Is it possible to draw a triangle with sides 150cm, 10 cm, and 10cm

2 answers:

7 0

<span>It is absolutely impossible to draw a triangle of sides 150 , 10 and 10 cm. With one side so large, it is impossible, which will make the two angles two small to intersect and the angle will be < 0, which is not possible in a triangle.

i hoped this helped </span>

hammer [34]3 years ago

5 0

Your possible answer is: NO. You cannot draw a triangle with side(s) 150 cm, 10 cm, and 10 cm - again. Sorry! Someone else has said no it's impossible. Or I mean YES it's impossible. Sorry . . . =( . . . =) XD

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8th grade math, please help.

Anastasy [175]

Answer:

32°

Step-by-step explanation:

since m ||n

x=32° ---- because corresponding angles are equal

8 0

3 years ago

9), Eva can knit f of a scarf in an hour. Her sister takes of the time she

solong [7]

Answer:

I don't think all of your question is there

4 0

3 years ago

Read 2 more answers

Alexa has some dimes and some quarters. She has a minimum of 28 coins worth a maximum of $5.05 combined. If Alexa has 17 quarter

vazorg [7]

Answer:

if she has 17 quarters, the money of it would be $4.25.

$5.05 - 4.25$ = $0.80

=> 8 dimes

=> she have 17 quarters and 8 dimes

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A study of the relationship between age and various visual functions (such as acuity and depth perception) reported the followin

maks197457 [2]

Answer:

(a) $\sum x_i=56.68$ and $\sum x_i^2=197.46$

(b) The sample variance is $s^2=0.530$ and the sample standard deviation is $s=0.728$

Step-by-step explanation:

(a)

The sum of these 17 sample observations is

$\sum x_i=2.79\:+2.57+\:2.73\:+3.75\:+2.27+\:2.75+\:4.00+\:4.22+\:3.88+\:4.35+\:3.41+\:4.57+\:2.38+\:3.73\:+2.75+\:3.47+\:3.06\\\\\sum x_i=56.68$

and the sum of their squares is

$\sum x_i^2=2.79^2\:+2.57^2+\:2.73^2\:+3.75^2\:+2.27^2+\:2.75^2+\:4.00^2+\:4.22^2+\:3.88^2+\:4.35^2+\:3.41^2+\:4.57^2+\:2.38^2+\:3.73^2\:+2.75^2+\:3.47^2+\:3.06^2\\\\\sum x_i^2=197.46$

(b)

The sample variance, denoted by $s^2$ , is given by

$s^2=\frac{S_{xx}}{n-1}$

where $S_{xx} =\sum x_i^2-\frac{(\sum x_i)^2}{n}$

Applying the above formula we get that

$S_{xx}=197.46-\frac{(56.68)^2}{17}\\\\S_{xx} =8.482$

$s^2=\frac{8.482}{17-1}=0.530$

The sample standard deviation, denoted by <em>s</em>, is the (positive) square root of the variance:

$s=\sqrt{s^2}$

Applying the above formula we get that

$s=\sqrt{0.530}=0.728$

3 0

3 years ago

Please explain how you got this answer

Alenkinab [10]

It gives 3 choices of toppings, and asks for the number of ways to arrange two toppings. Using the formula they give, n = 3 and k =2. So: $\frac{3!}{2!(3-2)!}$
Thus, the answer is 3.

4 0

3 years ago