The area between the two functions is 0
<h3>How to determine the area?</h3>
The functions are given as:
f₁(x)= 1
f₂(x) = |x - 2|
x ∈ [0, 4]
The area between the functions is
A = ∫[f₂(x) - f₁(x) ] dx
The above integral becomes
A = ∫|x - 2| - 1 dx (0 to 4)
When the above is integrated, we have:
A = [(|x - 2|(x - 2))/2 - x] (0 to 4)
Expand the above integral
A = [(|4 - 2|(4 - 2))/2 - 4] - [(|0 - 2|(0 - 2))/2 - 0]
This gives
A = [2 - 4] - [-2- 0]
Evaluate the expression
A = 0
Hence, the area between the two functions is 0
Read more about areas at:
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Answer:
20 miles in an hour.
Step-by-step explanation:
4/5=0.8
16/0.8=x/1
cross product
0.8*x=16*1
0.8x=16
x=16/0.8
x=20
<span>4(2h + g)
</span><span>4h + 4h +3g + g
</span>2(4h + 2g)
Pounds: 10 20 30
Kilos: 4.5 9 13.5
half of 20 is 10, and half of 9 is 4.5. So every 10 pounds is 4.5 kilos. Add 10 to 20 to get 30, and add 4.5 to 9 to get 13.5. Both parts of the ratio table are increasing at the same rate (either 10 eachtime or 4.5 each time).
Eq1) 2r+2s=50
eq2) 2r-s=17
solve for s in equation2 (eq2)
-s=17-2r
s=-17+2r
Substitute s into equation1 (eq1)
2r+2(-17+2r)=50
2r-34+4r=50
6r-34=50
6r=50+34
6r=84
r=14
Substitute into either equation and solve for s
2(14)-s=17
28-s=17
-s=17-28
-s=-11
s=11
