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densk [106]
3 years ago
9

What is the vertex form, f(x) = a(x − h)^2 + k, for a parabola that passes through the point (1, −7) and has (2, 3) as its verte

x. What is the standard form of the equation?
A) Vertex form: f(x) = 10(x + 4)^2 + 5
Standard form: f(x) = −10x^2 + 40x + 165

B) Vertex form: f(x) = −6(x − 4)^2 + 3
Standard form: f(x) = −6x^2 + 7x − 24

C) Vertex form: f(x) = −10(x − 2)^2 + 3
Standard form: f(x) = −10x^2 + 40x − 37

D) Vertex form: f(x) = −3(x − 2)^2 + 4
Standard form: f(x) = −3x^2 + 12x +16
Mathematics
1 answer:
pishuonlain [190]3 years ago
6 0

The vertex form of the equation is f(x)=-2(x-2)^2 - 4. The standard form of the equation is f(x)=-3x^2 + 12x - 16

ANSWER IS C

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Answers:

4 goes in the first box

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Explanation:

This piecewise function has 3 separate components to it:

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  • The center piece is y = 4. We leave the "y = " portion out and simply write 4 as the center piece. This says that the output is 4, but only when 0 <= x < 2. That will graph out a flat horizontal portion as the graph shows.
  • Lastly, the right-most piece is the line y = -2x+8. Again, we leave off the y portion and just write -2x+8. This piece only applies when 2 <= x < 4

Side note: Something like 2 <= x is another way of saying 2 \le x

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Answer:

  • See below

Step-by-step explanation:

<u>Given:</u>

  • Investment P = $20000
  • Time t = 7 years
  • Interest rate r = 5.5% = 0.055

a. <u>compounded semiannually, n = 2</u>

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b. <u>compounded quarterly, n = 4</u>

  • A = P*(1 + r/n)^{nt} = 20000(1+0.055/4)^{4*7} =  29315.30

c. <u>compounded monthly, n = 12</u>

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d. <u>compounded continuously</u>

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f(x)=2x^2-1

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f(-3)=2(-3)^2-1

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