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3 years ago

If you have two triangles with the same shape but one is twice as large as the other, are the triangles similar?

1 answer:

8 0

The triangles are similar because of one triangle is 2x bigger than the other there seems to be a dilation. And since on triangle is 2x bigger the dilation between both triangles would be 2. I hope this helped :)

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What 2 numbers multiply to be -14 and add to be -3

Svetach [21]

Xy = -14
x + y = -3

$xy = -14$
$\frac{xy}{x} = \frac{-14}{x}$
$y = \frac{-14}{x}$

$x + y = -3$
$x + \frac{-14}{x} = -3$
$\frac{x^{2}}{x} + \frac{-14}{x} = -3$
$\frac{x^{2} - 14}{x} = -3$
$x^{2} - 14 = -3x$
$x^{2} + 3x - 14 = 0$
$x = \frac{-(3) \± \sqrt{(3)^{2} - 4(1)(-14)}}{2(1)}$
$x = \frac{-3 \± \sqrt{9 + 56}}{2}$
$x = \frac{-3 \± \sqrt{65}}{2}$
$x = \frac{-3 \± 8.06}{2}$
$x = -1.5 \± 4.03$
$x = -1.5 + 4.03$ $or$ $x = -1.5 - 4.03$
$x = 2.53$ $or$ $x = -5.53$

  x + y = -3
2.53 + y = -3
- 2.53 - 2.53
  y = -5.53
  (x, y) = (2.53, -5.53)

x + y = -3
  -5.53 + y = -3
+ 5.53   + 5.53
  y = 2.53
  (x, y) = (-5.53, 2.53)

The two numbers that multiply to -14 and add up to -3 are -5.53 and 2.53.

8 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$