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Nata [24]
3 years ago
13

Please help me i really need help my question is at the bottom of the screen

Mathematics
1 answer:
photoshop1234 [79]3 years ago
8 0
I think the answer is choice B
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The volume of air in a balloon is represented by the function v(n) = ne?, where r is the radius of the balloon, in
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When V is composed with r, the composite function is StartFraction 1 Over 48 EndFraction pi t Superscript 6

V(r(6)) shows that the volume is 972π inches cubed when the radius increases to 6 inches.

Step-by-step explanation:

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I need help with my math
mrs_skeptik [129]

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42

Step-by-step explanation:

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Which is a like radical to ^3 sqrt 54 after simplifying?
Pachacha [2.7K]
\sqrt[3]{54} =  \sqrt[3]{2 \times 27} = 3 \sqrt[3]{2}
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3 years ago
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Please answer CORRECTLY !!!!!! WILL MARK BRAINLIEST !!!
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Answer:

5m

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-8n

Step-by-step explanation:

7m - 2m = 5m

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-5n - 3n = -8n

Have a great day

7 0
2 years ago
Directions for questions 4 & 5: We selected a random sample of 100 StatCrunchU students, 67 females and 33 males, and analyz
GaryK [48]

Answer:

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

The lower limit on the confidence interval is -$2164.21.

The upper limit on the confidence interval is -$299.13.

Step-by-step explanation:

The sample data is:

Gender   Mean          Std. dev.     n

Female    2577.75      1916.29     67

Male        3809.42     2379.47     33

We have to calculate a 95% confidence interval for the difference between means, with a T-model.

The sample 1, of size n1=67 has a mean of 2577.75 and a standard deviation of 1916.29.

The sample 2, of size n2=33 has a mean of 3809.42 and a standard deviation of 2379.47.

The difference between sample means is Md=-1231.67.

M_d=M_1-M_2=2577.75-3809.42=-1231.67

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1916.29^2}{67}+\dfrac{2379.47^2}{33}}\\\\\\s_{M_d}=\sqrt{54808.468+171572.045}=\sqrt{226380.513}=475.795

The t-value for a 95% confidence interval is t=1.96.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=1.96 \cdot 475.795=932.54

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = -1231.67-932.54=-2164.21\\\\UL=M_d+t \cdot s_{M_d} = -1231.67+932.54=-299.13

The 95% confidence interval for the difference between means is (-2164.21, -299.13).

6 0
3 years ago
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