Tell whether the unknown factor is less than 1 or greater than 1

Pls help me 35 points in total

garik1379 [7]

Answer:

1. = station A

because 15 gallons = 0.75 discount at B but station A has a 1.50 discount at 15 gallons

Step-by-step explanation:

2. for satation B you have to read the graph

but for station A it is unclear on the graph

a way to work it out is that you know that 10= 1.00 so 12 = 1.2

( divide 12 by 10 )

station B = discount for 12 gallons = 0.6

but Station A = discount for 12 gallons = 1.2

the difference is

1.2 - 0.6 = 0.6 discount

3 0

3 years ago

Solve the equation. 8x2 – 4 = 28

Flura [38]

Hello,

Your answer would be 2, -2.

$8x^2 - 4 = 28$

$8x^2-4+4=28+4$

$8x^2 = 32$

$\frac{8x^2}{8}= \frac{32}{8} 
$

$x^2 = 4$

x = +/4

x = 2 or x = -2

2 , -2 would be the answer! :)

Mark Brainliest if this helped you :)

4 0

3 years ago

Read 2 more answers

The following is a linear sequence. 1, 4, 7, 10, 13...

jasenka [17]

We have

$a_n = 3n - 2$

We're asked for $a_{90}$

$a_{90} = 3(90) - 2 = 268$

Answer: C 268

8 0

4 years ago

For a large supermarket chain in a particularâ state, aâ women's group claimed that female employees were passed over for manage

PolarNik [594]

Answer:

1) As the P-value (0.097) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the women's claim that female employees were passed over for management training in favor of their male colleagues.

2) The 95% confidence interval for the population proportion is (0.173, 0.427).

The populations proportion (π=0.4) is included in this confidence interval, so the claim has no enough evidence to be supported.

Step-by-step explanation:

This is a hypothesis test for a proportion.

The claim is that female employees were passed over for management training in favor of their male colleagues.

We use the women's part for sample and population proportions.

Then, the null and alternative hypothesis are:

$H_0: \pi=0.4\\\\H_a:\pi$

The significance level is 0.05.

The sample has a size n=50 persons.

The sample proportion is p=0.3.

$p=X/n=15/50=0.3$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.4*0.6}{50}}\\\\\\ \sigma_p=\sqrt{0.0048}=0.069$

Then, we can calculate the z-statistic as:

$z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.3-0.4+0.5/50}{0.069}=\dfrac{-0.09}{0.069}=-1.299$

This test is a left-tailed test, so the P-value for this test is calculated as:

$\text{P-value}=P(z$

As the P-value (0.097) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that female employees were passed over for management training in favor of their male colleagues.

b) We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.3.

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.3*0.7}{50}}\\\\\\ \sigma_p=\sqrt{0.0042}=0.0648$

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

$MOE=z\cdot \sigma_p=1.96 \cdot 0.0648=0.127$

Then, the lower and upper bounds of the confidence interval are:

$LL=p-z \cdot \sigma_p = 0.3-0.127=0.173\\\\UL=p+z \cdot \sigma_p = 0.3+0.127=0.427$

The 95% confidence interval for the population proportion is (0.173, 0.427).

The populations proportion (π=0.4) is included in this confidence interval, so the claim has no enough evidence to be supported.

5 0

3 years ago

Please help me vote you brainiest

Vikki [24]

Answer:

B

Step-by-step explanation:

He can make 14 whole dumplings

4 0

3 years ago

Read 2 more answers