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Alexandra [31]
3 years ago
8

What is the multiplicative of 6

Mathematics
1 answer:
ankoles [38]3 years ago
8 0
The multiplicative of 6 is 1/6
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Pitágoras filósofo matemático griego biblio entre los años 500 8496 antes de Cristo A qué edad murió y cuántos años hace que mur
Maurinko [17]

Answer:

if you can transfer to englis i may be able to help

Step-by-step explanation:

5 0
3 years ago
Given the following sequence:<br>3,6,12,24​
Mars2501 [29]

Answer:

It is a GP.

Step-by-step explanation:

a = 3

r = 2

a(n) term = ar^n

As it increases as multiples, it is a geometric progression or a GP.

8 0
2 years ago
Given the following acceleration function of an object moving along a line, find the position function with the given initial ve
Nezavi [6.7K]

Answer:

Position function is s(t)=-12t^2

Step-by-step explanation:

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5 0
2 years ago
Convert the Cartesian equation x - 5 = 0 to a polar equation.
mylen [45]

Answer:

  r = 5sec(θ)

Step-by-step explanation:

The usual conversion is ...

  y = r·sin(θ)

  x = r·cos(θ)

__

The second of these can be used here.

  r·cos(θ) -5 = 0

  r·cos(θ) = 5

  r = 5/cos(θ) = 5sec(θ)

A suitable polar equation is ...

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5 0
2 years ago
Eric wants to get an output of 0. Can he do this with each machine? If so, how? If not, why not?
natita [175]

Answer:

  • <u>No, he can get an output of 0 with the second machine (function B) but he cannot get an output of 0 with the first machine (function A).</u>

Explanation

The way each machine works is given by the expression (function) inside it.

<u>1)  </u><em><u>Function A</u></em>

To get an output of 0 with the function y = x² + 3, you must solve the equation x² + 3 = 0.

Since x² is zero or positive for any real number, x² + 3 will never be less than 3 (the minimum value of x² + 3 is 3). So, it is not possible to get an output of 0 with the first machine.

<u>2) </u><em><u>Function B</u></em>

Solve y=\sqrt{x}-2=0

  • \sqrt{x}-2=0

  • \sqrt{x} =2

  • x=2^{2}

  • x=4

So, he can get an output of 0 by using x = 4.

4 0
2 years ago
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