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Lisa [10]
3 years ago
7

Write an equation for the line that is parallel to the given line and passes through the given point

Mathematics
2 answers:
Lana71 [14]3 years ago
8 0
Y = 5x+4. The slope is the same, 5, making them parallel, and when you plug in 2 for x you get 14
victus00 [196]3 years ago
3 0

Answer:

y = 5x+4

Step-by-step explanation:

For this case we have the following equation:

y = 5x +10

And we want a line parallel to this one that passes thourgh the point (2,14). In order to satisfy this we need that condition:

m_1 = m_2 =5

Where m_1 = 5 on this case for the original slope, and if we solve for m_2 we got:

m_2 = 5

And now since we have the new slope we can solve for the value of b like this:

14 = 5*(2) + b

And if we solve for b we got:

b = 14- 10= 4

And then our equation parallel is given by:

y = 5x+4

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If i’m correct it’s y=2 im 99% sure
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-8x - 11x<br> I really need help
Tema [17]

Answer: -19x

Step-by-step explanation: In this problem, we're asked to simplify the expression.

The two parts of this expression, -8x and 11x are called terms. The numbers in front of the variables are called coefficients.

Because the variables, x and x are identical, the terms get a special name and they're called like terms.

To subtract like terms, we simply subtract their coefficients and add the variable on to the difference of the two numbers.

Since -8 (-11) is -19, -8x - 11x simplifies to -19x.

4 0
3 years ago
PLEASSEEE I NEED HELPP
Alex777 [14]

Answer:

b=5V2

Step-by-step explanation:

Area =31 1/4 = b*12.5 sin45/2=b*12.5*V2/2* 1/2=12.5V2/4 *b

(31*4+1)/4=125/4

so 125/4= 12.5V2*b/4

12.5V2*b=125

b=125/12.5V2=10/V2=10V2/2=5V2

3 0
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