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Lisa [10]
3 years ago
7

Write an equation for the line that is parallel to the given line and passes through the given point

Mathematics
2 answers:
Lana71 [14]3 years ago
8 0
Y = 5x+4. The slope is the same, 5, making them parallel, and when you plug in 2 for x you get 14
victus00 [196]3 years ago
3 0

Answer:

y = 5x+4

Step-by-step explanation:

For this case we have the following equation:

y = 5x +10

And we want a line parallel to this one that passes thourgh the point (2,14). In order to satisfy this we need that condition:

m_1 = m_2 =5

Where m_1 = 5 on this case for the original slope, and if we solve for m_2 we got:

m_2 = 5

And now since we have the new slope we can solve for the value of b like this:

14 = 5*(2) + b

And if we solve for b we got:

b = 14- 10= 4

And then our equation parallel is given by:

y = 5x+4

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Find the measure of one interior angle in each regular polygon. round your answer to the nearest 10th if necessary.
Artist 52 [7]
S = (n-2) * 180
s = (14-2) * 180
s = 2160
2160/ 14 = 154.3
The answer is A
4 0
2 years ago
Read 2 more answers
Rewrite in simplest terms:
tangare [24]

Answer:

If one −5s−7(8s−1): -61s+7

If two −5s−7(8s−1): -112s+14

Step-by-step explanation:

-5s-7(8s-1)

Multiply -7 onto 8s and -1:

-5s-56s+7

add -5s and -56s:

-61s+7

−5s−7(8s−1)−5s−7(8s−1)

Multiply both -7 to 8s and -1

-5s-56s+7-5s-56s+7

add:

-112s+14

6 0
3 years ago
A line passes through the point (-10,8) and has a slope of 1/2.
timofeeve [1]

Answer:

the answer is y=1/2x+13

6 0
3 years ago
In rectangle abcd, points p and q lie on side AB and DC respectively. Angle PMQ is a right angle, M is the midpoint of side BC a
nirvana33 [79]

Answer:

PM:MQ = 8:3.

Step-by-step explanation:

\rm \angle B\hat{M}P + 90^{\circ} + \angle C\hat{M}Q = 180^{\circ};

\implies \rm \angle B\hat{M}P + \angle C\hat{M}Q = 90^{\circ};

\implies \rm 90^{\circ} - \angle B\hat{M}P = \angle C\hat{M}Q.

Also,

\rm \angle B\hat{P}M = 90^{\circ} - \angle B\hat{M}P in right triangle PBM.

Thus \rm \angle{P\hat{B}M} = \angle C\hat{M}Q.

Additionally \rm \angle \hat{B} = 90^{\circ} = \angle \hat{C}.

Therefore \rm \triangle PBM \sim \triangle MCQ.

\rm \displaystyle BC = 2\;MC for M is the midpoint of segment BC.

\rm \displaystyle PB = \frac{4}{3}BC = \frac{8}{3}MC.

\rm \triangle PBM \sim \triangle MCQ implies that

\displaystyle \rm PM:MQ = PB:MC = 1:\frac{8}{3} = 8:3.

8 0
3 years ago
3 points that equal y=x+6
-BARSIC- [3]
(0,6),(4,10),(1,7), all you need to do is find a random y value and add 6 to it to get the x value.
5 0
3 years ago
Read 2 more answers
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