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ziro4ka [17]
3 years ago
11

Complete the generic rectangle (PLEASE HELP)

Mathematics
1 answer:
navik [9.2K]3 years ago
4 0

I believe the area of the blank rectangle, the biggest one, is 2800. The whole rectangle all together is 3225.

Explanation:

Since the length of one of the rectangles is 70, the rectangle with an area of 210 will have a side length of 3. This means the rectangle with an area of 15 has a side length of 5. <em>That</em> means the rectangle with an area of 200 has a side length of 40. Therefore, the blank rectangle has an area of 2800, as it's 2 side lengths are 70 and 40.

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Find the product. (-2x^2 )^3 ·3 x
jeka94

Assignment: \bold{Solve \ \left(-2x^2\right)^3\cdot \:3x}

<><><><><>

Answer: \boxed{\bold{-24x^7}}

<><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><>

[ Step One ] Rewrite \bold{\left(-2x^2\right)^3}

\bold{-2^3\left(x^2\right)^3}

[ Step Two ] Rewrite Equation

\bold{-2^3\cdot \:3x^6x}

[ Step Three ] Apply Exponent Rule

Note: \bold{Exponent \ Rule \ \:a^b\cdot \:a^c=a^{b+c}: \ x^6x=\:x^{6+1}=\:x^7}

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[ Step Four ] Refine

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\bold{\rightarrow Rhythm \ Bot \leftarrow}

4 0
3 years ago
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ms evans went to the store to buy some cupcakes. she brought 129 cupcakes. she wants to put 5 cupcakes in each box.how many boxe
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This means that she will need a total of 26 boxes, but only 25 of them will have 5 cupcakes in them. The last one will have 4 cupcakes.
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Step-by-step explanation:

A=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]

B=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]

C=\left[\begin{array}{ccc}-2&3&1\\-1&0&4\end{array}\right]

D=\left[\begin{array}{ccc}-2&3&4\\0&-2&1\\3&4&-1\end{array}\right]

1.\\A+B=\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]+\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]=\left[\begin{array}{ccc}3+4&1+1\\5+6&7+0\end{array}\right]=\left[\begin{array}{ccc}7&2\\11&7\end{array}\right]

2.\\B-A=\left[\begin{array}{ccc}4&1\\6&0\end{array}\right]-\left[\begin{array}{ccc}3&1\\5&7\end{array}\right]=\left[\begin{array}{ccc}4-3&1-1\\6-5&0-7\end{array}\right]=\left[\begin{array}{ccc}1&0\\1&-7\end{array}\right]

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