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3 years ago

If someone could do this exam for me I'll do anything else school related!

Mathematics

1 answer:

trapecia [35]3 years ago

3 0

C. just shorten fraction and you'll only get 1/(y²z²)
you'll get (6xy²z²)/(6xy⁴z⁴)=1/(y²z²)

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Maria received 5/7 of the 42 votes cast for class president. how many votes did she receive?

baherus [9]

42/7= 6
5*6=30
30 votes

6 0

3 years ago

A truck is being filled with cube-shaped packages that have side lengths of 1/4 foot. The part of the truck that is being filled

n200080 [17]

Answer:

24000 pieces.

Step-by-step explanation:

Given:

Side lengths of cube = $\frac{1}{4} \ foot$

The part of the truck that is being filled is in the shape of a rectangular prism with dimensions of 8 ft x 6 1/4 ft x 7 1/2 ft.

Question asked:

What is the greatest number of packages that can fit in the truck?

Solution:

First of all we will find volume of cube, then volume of rectangular prism and then simply divide the volume of prism by volume of cube to find the greatest number of packages that can fit in the truck.

$Volume\ of\ cube =a^{3}$

$=\frac{1}{4} \times\frac{1}{4}\times \frac{1}{4} =\frac{1}{64} \ cubic \ foot$

Length = 8 foot, Breadth = $6\frac{1}{4} =\frac{25}{4} \ foot$ , Height = $7\frac{1}{2} =\frac{15}{2} \ foot$

$Volume\ of\ rectangular\ prism =length\times breadth\times height$

$=8\times\frac{25}{4} \times\frac{15}{2} \\=\frac{3000}{8} =375\ cubic\ foot$

The greatest number of packages that can fit in the truck = Volume of prism divided by volume of cube

The greatest number of packages that can fit in the truck = $\frac{375}{\frac{1}{64} } =375\times64=24000\ pieces\ of\ cube$

Thus, the greatest number of packages that can fit in the truck is 24000 pieces.

7 0

3 years ago

HELP MEEE PLEASEE SHOOW UR WOORRKK

stiks02 [169]

Answer:

Step-by-step explanation:

2(k-5)+3k=k+6

step 1 distribute the 2 to whats in the parenthesis

2k-10+3k=k+6

step 2 combine any like terms if there are any

5k-10=k+6

step 3 add 10 to each side

5k=k+16

step 4 subtract 1k from each side

4k=16

step 5 divide each side by 4

k=4

6 0

3 years ago

The weights of 1,000 men in a certain town follow a normal distribution with a mean of 150 pounds and a standard deviation of 15

uysha [10]

Z = ( 135 - μ ) / σ = -1
z = ( 165 - μ ) / σ = 1
P (x < 135) = P (z < -1) = 0.1587
P (165 < x) = P (1 < z) = 0.1587
.187 * 1000 = 187 more than 165
<span>.187 * 1000 = 187 less than 135</span>

7 0

4 years ago

Help!!!!! Include working out please.

Anni [7]

What question do you need help with? You have to include that!

6 0

3 years ago