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Rudik [331]
2 years ago
11

a population has a mean of 25 median of 24 and mode of 26 the standard deviation is 5 the value for the

Mathematics
1 answer:
Arada [10]2 years ago
3 0

Complete Question

A population has a mean of 25, a median of 24, and a mode of 26. The standard deviation is 5. The value of the 16th percentile is _______. The range for the middle 3 standard deviation is _______.

Answer:

The  value  of the 16th percentile  is  x = 20

The range for the middle 3 standard deviation is  10 \to 40

Step-by-step explanation:

From the question we are told that

     The  mean is  \mu  =  25

     The  median is  m  =  24

     The  mode is  n =  26

     The  standard deviation is  \sigma  =  5

Generally the 16th percentile is mathematically represented as

  P(x)= P(\frac{X  -  \mu }{ \sigma }   \le \frac{x- 25 }{5} ) = 0.16[/teGenerally  [tex]\frac{X -  \mu}{\sigma }  =  Z(The  \  standardized \  value \ of  \ X  )

So

       P(x) =  P(Z \le \frac{ x -  25}{5} ) =  0.16

Now from the normal distribution table  the z-score of  0.16 is  

      z =  -1

       P(x) =  P(Z \le \frac{ x -  25}{5} ) =  P(Z \le -1 )

=>  \frac{x- 25}{5}  =  -1

=>    x- 25  =  -5

=>      x =  25-5

=>       x = 20

The range for the middle 3 standard deviation is mathematically represented

        \mu  -  3\sigma \to \mu + 3\sigma

        25 -  3(5 ) \to 25 +  3(5 )

         10 \to 40

 

   

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Let's put these equations in the form y = kx.

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