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Scilla [17]
3 years ago
9

What is the solution to an equation /

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

Idk what u mean?

Step-by-step explanation:

but i searched it up and here are my results

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true. For equations having one unknown, raised to a single power, two fundamental rules of algebra, including the additive property and the multiplicative property, are used to determine its solutions.Mar 20, 2020

email me if it helps

ty

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Plss help...<br><br>Write down the rule in the form y=​
aniked [119]

Answer:

yxthgggggyhfffghgggggvggvvggvv

6 0
2 years ago
Oil is often measured in barrels one barrel can hold the 42 gallons of oil how many gallons of oil can 7 barrels hold
svetoff [14.1K]
294 gallons of oil is the answer because you do 42 and mltiply it by 7
7 0
3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0
3 years ago
Simplify<br> (3m²n4)3<br> O 9m5 n?<br> O 9m6n12<br> O 27mn12<br> O 27mn?
Lana71 [14]

Answer:

(3m2n4)^3

Step-by-step explanation:

This deals with raising to a power.

(3m2 • (n4))3

m2 raised to the 3 rd power = m( 2 * 3 ) = m6

n4 raised to the 3 rd power = n( 4 * 3 ) = n12

7 0
3 years ago
Help, thank you!
kaheart [24]

Answer:

√357

Step-by-step explanation:

multiply all three numbers together and since 357 cannot be simplified it stays as a radical

8 0
3 years ago
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