Answer:
F = -6 + 2d/5
Step-by-step explanation:
2d-5f=30
subract 2D from each side
-5f=30-2d
divide both sides by -5
f= -6 +2d/5
Answer:
Step-by-step explanation:
area becomes 2²=4 times.
Answer: x(t) = 5cm*cos(t*pi/2s)
Step-by-step explanation:
This is a sinusoidal equation, so we can write this as:
x(t) = A*cos(c*t + p) + B
where B is the axis around the movement, as the resting position is x = 0, we have B = 0
so x(t) = A*cos(c*t + p)
A is the amplitude of the oscilation, c is the frequency and p is a phase.
We know that when t = 0s, we have x(2s) = 5cm
if this is the maximum displacement, then knowing that the maximum of the cosine is cos(0) = 1
then we must have that p = 0
x(0s) = A*cos(0) = 5cm
then we have A = 5cm
Now, when t = 2s, we have:
x(2s) = 5cm*cos(2s*c) = -5cm
then 2s*c is the minimum of the cos(x) function, this is:
cos(pi) = -1
then 2s*c = pi
c = pi/2s.
then our function is:
x(t) = 5cm*cos(t*pi/2s)
Answer:
109.3 yard²
Step-by-step explanation:
Area of triangle = bh / 2
base is 23yd
height is 9.5yd
bh / 2 = 23 × 9.5 / 2
Area = 218.5 / 2
Area = 109.25 yd²; rounded to the nearest tenth is 109.3yd²
Answer:
456.25m
Step-by-step explanation:
Since the question did not ask for what to find, we can as well look for the maximum height reached by the object
Given the height of an object thrown vertically expressed as;
s=-16t^2+100t+200.
At max height,
dS/dt = 0
-32t+100 = 0
-32t = -100
t = 100/32
t = 3.125s
Get the Max height
s(3.125) = -16(3.125)²+100(3.125)+200
s(3.125) = -156.25+312.5+200
s(3.125) = 456.25m
Hence the maximum height reached by the object is 456.25m
