a) substitution (refer to statements 1 and 2)
b) definition of supplementary
c) subtraction property of equality
Answer:
From the graph we can say that ant is moving faster than the ladybug
Slope of the ant's movement will be steeper than the ladybug
- Hence<u>, </u><u>line "</u>v" denotes the speed of ant and <u>line "</u>u" denotes the speed of ladybug.
Unit rate/slope of the graph is (distance traveled/elapsed time)
- <u>Unit rate of ant is 3/2 cm/sec</u> and <u>that of ladybug is 1 cm/sec.</u>
- Ant takes (12×2/3) =<u> </u><u>8</u><u> </u><u>sec</u> and ladybug takes (12×1) =<u> </u><u>12</u><u> </u><u>sec</u> to travel 12 cm.
Remember ant will take less time to travel a certain distance than ladybug.
Answer:
15x+25 ; 70
Step-by-step explanation:
Given that,
Fernando cleans pools for the summer for $25 an hour plus a supply fee of $15.
Here, $25 is constant and $15 increases as the number of hour increase. For x hours, the cost for Fernando to clean a pool is given by :
y = 15x+25
For 3 hours,
y = 15(3)+25
= 45 + 25
= 70
So, the required option is (c) " 15x+25 ; 70 ".
Answer:
Relative frequency
0.214
0.268
0.446
0.071
Total 1
Step-by-step explanation:
The relative frequency is computed by dividing the individual frequencies to the sum of frequencies.
sum of frequencies=12+15+25+4=56
Class Relative Frequency
10-20 12/56=0.214
20-30 15/56=0.268
30-40 25/56=0.446
40-50 4/56=0.071
Total 12/56+15/56+25/56+4/56=56/56=1
