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o-na [289]
3 years ago
5

Lymphatic fluid contains mostly A. thrombocytes. B. lymphocytes. C. red blood cells. D. neutrophils.

Biology
1 answer:
Darina [25.2K]3 years ago
3 0
Lymphocytes.
Hope this helps! :)
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1)The picture is an aerial view of what and what type boundary forms this feature?
melamori03 [73]

Answer:

The correct answer is - aerial view of the fault line of San Andreas which represents a transform or strike-slip type of boundary.

Explanation:

The picture is given in the question is an aerial view of the fault line of San Andreas.

A fault is a planar break or intermittence in a volume of rock across due to rock-mass movement that leads to significant relocation or displacement. In San Andreas, the faultline represents the transform or strike-slip type of boundary.

Observation:

  1. A complex zone of crushed and broken rock
  1. Many smaller faults branch
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How might a single base substitution in the sequence of a gene affect the amino acid sequence of a protein encoded by the gene,
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The effect differs. It could produce a different amino acid in the sequence because the corresponding codon has changed. It could also prevent the production of the originally intended sequence by changing one of the amino acids of a "start" codon (aka AUG) or extend the protein's sequence by modifying a "stop" codon (UAA, UAG, UGA or UGG), producing a new protein that might be useless or have different effects on the cell.
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3 years ago
What does a trace fossil look like?​
Arisa [49]

Answer:

Trace fossils include footprints, trails, burrows, feeding marks, and resting marks.

Explanation:

6 0
3 years ago
5. Atoms with a(n) blank share electrons.
lyudmila [28]

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3 0
3 years ago
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A locus that affects susceptibility to a degenerative brain disease has two alleles, V and v. In a population, 16 people have ge
Pie

Answer:

Yes, the population is evolving

Explanation:

Hardy-Weinberg equilibrium states that a population is not evolving if it is in hardy weinberg equilibrium as the alleles frequency do not change over time in generations.

In mathematical equation, the genotype frequency will be -P²+2Pq+q²=1 and allele frequency will be p+q=1, where p = dominant allele and q will be recessive allele.

In the question, since the observed genotype are-

P² - VV= 16

2Pq- Vv- 92

q²- vv- 12

<u>1. Calculate allele frequency</u>

Now we will calculate if the expected value is same or close or not.

We will calculate allele frequency

Population has 120 individuals which means it has - 240 alleles.

In which V (p) will be- 32 +92= 124 allele

p- dominant allele/ total allele=  124/ 240 = 0.52

P= 0.52

q will be 1-0.52= 0.48

<u>2. Expected genotype frequency</u>

Now we will calculate expected genotypic frequency.

P²- 0.52 X 0.52= 0.27

2Pq = 2 x 0.52x 0.48 =  0.5

q²= 0.48 x 0.48 =  0.23

<u>3. Expected progeny </u>

P²= 0.27 x 120= 32 VV

2Pq= 0.5 X 120= 60 Vv

q²= 0.23 x 120= 28 vv

Since the observed value is not equal to the expected value therefore the population is not in Hardy- Weinberg equilibrium and the population is evolving.

Thus, Yes, the population is evolving is correct.

4 0
4 years ago
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