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zzz [600]
3 years ago
11

What is the equation of a line with a y-intercept at (0,6) and a slope of 3?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
8 0

Answer: answer A

Step-by-step explanation: y = mx + b

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For the hypothesis test H0: μ = 10 against H1: μ >10 and variance known, calculate the Pvalue for each of the following test
Basile [38]

Answer:

a) p_v =P(Z>2.05)=1-P(z

b) p_v =P(Z>-1.84)=1-P(z

c) p_v =P(Z>0.4)=1-P(z

Step-by-step explanation:

Some previous concepts

The p-value is the probability of obtaining the observed results of a test, assuming that the null hypothesis is correct.

A z-test for one mean "is a hypothesis test that attempts to make a claim about the population mean(μ)".

The null hypothesis attempts "to show that no variation exists between variables or that a single variable is no different than its mean"

The alternative hypothesis "is the hypothesis used in hypothesis testing that is contrary to the null hypothesis"

Hypothesis

Null hypothesis: \mu=10

Alternative hypothesis: \mu >10

If the random variable is distributed like this: X \sim N(\mu,\sigma)

We assume that the variance is known so the correct test to apply here is the z test to compare means, the statistic is given by the following formula:

z_o=\frac{\bar X -\mu}{\sigma}

Since we have the values for the statistic already calculated we can calculate the p value using the following formulas:

Part a

p_v =P(Z>2.05)=1-P(z

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(2.05,0,1,TRUE)"

Part b

p_v =P(Z>-1.84)=1-P(z

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(-1.84,0,1,TRUE)"

Part c

p_v =P(Z>0.4)=1-P(z

And in order to find the answer using excel we can use the following code:

"=1-NORM.DIST(0.4,0,1,TRUE)"

Conclusions

If we use a reference value for the significance, let's say \alpha=0.05. For part a the p_v so then we can reject the null hypothesis at this significance level.

For part b the p_v>\alpha so then we FAIL to reject the null hypothesis at this significance level.

For part c the p_v>\alpha so again we FAIL to reject the null hypothesis at this significance level.

3 0
3 years ago
Square has side lengths of 13 units. Point lies in the interior of the square such that units and units. What is the distance fr
romanna [79]

The distance from E to side AD is 25/13.

<h3>What is a distance?</h3>
  • The length of the line connecting two places is the distance between them.
  • If the two points are on the same horizontal or vertical line, the distance can be calculated by subtracting the non-identical values.

To find what is the distance from E to side AD:

  • If you draw a diagram, you'll see that triangle AEB is a right triangle with lengths 5, 12, and 13.
  • Let's call F the point where E meets side AD, so the problem is to find the length of EF.
  • By Angle-Angle Similarity, triangle AFE is similar to triangle BEA. (the right angles are congruent, and both angle FAE and ABE are complementary to angle BAE)
  • Since they're similar, the ratios of their side lengths are the same.
  • EF/EA = EA/AB (they're corresponding side lengths of similar triangles).

Substitute them with known lengths:

  • EF/5 = 5/13
  • EF = 5 × (5/13) = 25/13

Therefore, the distance from E to side AD is 25/13.

Know more about distance here:

brainly.com/question/2854969

#SPJ4

The correct answer is given below:
Square ABCD has side lengths of 13 units. Point E lies in the interior of the square such that AE=5 units and BE=12 units. What is the distance from E to side AD? Express your answer as a mixed number.

8 0
1 year ago
Factor.<br> x^2+25<br><br> (x+5) (x-5) <br> (x+5) (x+5)<br> (x+5i) (x-5i)<br> (x+5i) (x+5i)
icang [17]

Answer:

( x + 5 i ) ( x − 5 i )

Step-by-step explanation:

Multiply the constant by  − i ^2  and factor.

4 0
3 years ago
How to answer a problem that says 5 ro the 4 power over 5
Eddi Din [679]

\bf ~~~~~~~~~~~~\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} \qquad \qquad \cfrac{1}{a^n}\implies a^{-n} \qquad \qquad  a^n\implies \cfrac{1}{a^{-n}} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \cfrac{5^4}{5}\implies 5^4\cdot 5^{-1}\implies 5^{4-1}\implies 5^3\implies 125

4 0
3 years ago
Perform the indicated operation​ and, if​ possible simplify<br> 2/3-1/7
Fiesta28 [93]
11/21 would be the answer
3 0
3 years ago
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