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Setler79 [48]
3 years ago
6

What is the equation of the line that passes through the point (-2, 6) and has a slope of -3?

Mathematics
1 answer:
poizon [28]3 years ago
3 0

Answer:

y=-3x

Step-by-step explanation:

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A particle moves along the x-axis so that at time t its position is given by s(t) = (t + 1)(t - 3)3, t > 0. /p>For what va
Zepler [3.9K]

Given the position function, the velocity function is obtained by taking the derivative:

s(t)=(t+1)(t-3)^3\implies v(t)=(t-3)^3+3(t+1)(t-3)^2

The velocity is increasing its own derivative is positive, so we also have to find the acceleration by taking another derivative:

a(t)=4(t-3)^3+3(t-3)^2+6(t+1)(t-3)

To find when a(t)>0, we first need to know where a(t)=0:

4(t-3)^3+3(t-3)^2+6(t+1)(t-3)=(t-3)\bigg(4(t-3)^2+3(t-3)+6(t+1)\bigg)=(t-3)(4t^2-15t+33)=0

The quadratic factor is always positive (its discriminant is negative), which leaves one solution at t=3. To either side of t=3, we have, for instance,

a(2)=-12

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which indicates that v(t) is increasing for t>3, making the answer A.

5 0
3 years ago
Answers for both boxes please ​
xxTIMURxx [149]

Answer:

(-3, -6)

Step-by-step explanation:

y=2x

-3x-15=y

Use Substitution Method

-3x-15=2x

+3x      +3x

-15=5x

/5   /5

-3=x

y=2x

y=2(-3)

y=-6

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