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Setler79 [48]
3 years ago
6

What is the equation of the line that passes through the point (-2, 6) and has a slope of -3?

Mathematics
1 answer:
poizon [28]3 years ago
3 0

Answer:

y=-3x

Step-by-step explanation:

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Help please! any1 know this​
worty [1.4K]

The only option that fits is E, because:

f(10)=4×10+10=50

8 0
3 years ago
Which would be the next number in the pattern?<br> 36, 49, 64, 81 __
swat32

Answer:

100

Step-by-step explanation:

hope this helps

have a good day

4 0
2 years ago
Read 2 more answers
a baker used 660 boxes of cake mix to make a wedding cake. if each box called for 3 eggs, how many dozen eggs were used to make
yanalaym [24]
We know there’s 660 boxes and each box called for 3 eggs, therefore:

660=3X

when divide both sides by 3 to isolate the x, which will tell us the amount of eggs used…

660/3 = 220
6 0
2 years ago
What is the solution to y=2/5x-3 and x=-10
Vanyuwa [196]

y is -2/53

Step-by-step explanation:

  • Step 1: Given equation is y = 2/5x-3 and x = -10. Substitute value of x to find the solution.

⇒ y = 2/(5 × -10 - 3) = 2/-53 = -2/53

4 0
3 years ago
What is the interquartile range of the data set ​
Verizon [17]

There are many methods of doing this. This one finds the median; however, instead of halving, you can use quarters instead.

First order the data, ascendingly:

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

Find the median:

For an even number of values: The number of values / 2

For an odd number of values: The number of values + 1 / 2

11 is odd.

11 + 1 / 2

12 / 2 = 6

The median is at the 6th position.

10, 17, 18, 18, 18, 20, 20, 25, 25, 30, 30

The median is 20.

<em>Other method:</em>

<em>You don't need this step.</em>

Using the values lower than the median, exclusive, find the median of the lower values;

For an odd number of values: <u>The number of values + 1 / 2</u>

10, 17, 18, 18, 18

5 + 1 / 2 = 6 / 2 = 3

The median of the lower values is at position 3.

This is the lower quartile.

10, 17, 18, 18, 18

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>The number of values + 1 / 4</em></u>

<em>11 + 1 / 4 = 12 / 4 = 3</em>

<em>10, 17, </em><em>18,</em><em> 18, 18, 20, 20, 25, 25, 30, 30</em>

<em />

Using the values greater than the median, exclusive, find the median:

For an odd number of values: <u>The number of values + 1 / 2</u>

20, 25, 25, 30, 30

5 + 1 / 2 = 6 / 2 = 3

The median of the upper values is at position 3.

20, 25, 25, 30, 30

This is 25.

This is the upper quartile.

<em>Other method:</em>

<em>For an odd number of values: </em><u><em>(The number of values + 1 / 4) * 3</em></u>

<em>(11 + 1 / 4) * 3 = (12 / 4)  * 3 = 3 * 3 = 9</em>

<em>10, 17, 18</em><em>,</em><em> 18, 18, 20, 20, 25, </em><em>25</em><em>, 30, 30</em>

Your interquartile range is 3 - 25

25 - 3 = 21

<h2>21</h2>
8 0
3 years ago
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