The answer of this question is??

I have a bag of trail mix. One half of the bag is peanuts 1/4 of the bag is chocolate candies,1/4 of the bag is dried fruit. Wha

lana66690 [7]

50% or 1/2 or 1:2 would be your answer

3 0

2 years ago

The chorus has 30 members. What expression represents the number of ways a group of 6 members can be chosen to do a special perf

RoseWind [281]

The problem uses the concept of Combination where there are number of members chosen from a group and there order is not important. Thus, the expression that would best describe the given above is 30C6 which means the combination of 30 taken 6. The numerical value for this is 593775.

8 0

3 years ago

Read 2 more answers

A triangle is given by A ( 3,2 ) B (-1,5) and C (0,-1) . What is the equation of the line through B parallel to AC ( give ans an

Leokris [45]

Answer:

Step-by-step explanation:

Solution :

hello :

note :

Use the point-slope formula.

y - y_1 = m(x - x_1) when : x_1= -1 y_1= 5

m= the slope is : (YC - YA)/(XC -XA)

(-1-2)/(0-3) = -3/-3 =1

( parallel to AC means same slope)

an equation in the point-slope form is : y -5 = 1(x+1)

y=x+6

6 0

1 year ago

How do you solve his with working

AlexFokin [52]

Check the picture below.

a)

so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.

the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".

let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.

and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.

$\bf \begin{array}{cllll}
\textit{circumference of a circle}\\\\ 
2\pi r
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{arc's length}\\\\
s=\cfrac{\theta r\pi }{180}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{green~circle}{perimeter}}{2\pi(7.5) }~-~\stackrel{\stackrel{green~circle}{arc}}{\cfrac{(135)(7.5)\pi }{180}}~+
\stackrel{\stackrel{red~section}{perimeter}}{2\pi(9.5) }~-~\stackrel{\stackrel{red~section}{arc}}{\cfrac{(135)(9.5)\pi }{180}}+\stackrel{endpoints}{2+2}
\\\\\\
15\pi -\cfrac{45\pi }{8}+19\pi -\cfrac{57\pi }{8}+4\implies \cfrac{85\pi }{4}+4\quad \approx \quad 70.7588438888$

b)

we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.

$\bf \begin{array}{cllll}
\textit{area of a circle}\\\\ 
\pi r^2
\end{array}\qquad \qquad \qquad \qquad 
\begin{array}{cllll}
\textit{area of a sector of a circle}\\\\
s=\cfrac{\theta r^2\pi }{360}
\end{array}\\\\
-------------------------------$

$\bf \stackrel{\stackrel{red~section}{area}}{\pi(9.5^2) }~-~\stackrel{\stackrel{red~section}{sector}}{\cfrac{(135)(9.5^2)\pi }{360}}-\stackrel{\stackrel{green~circle}{sector}}{\cfrac{(225)(7.5^2)\pi }{360}}
\\\\\\
90.25\pi -\cfrac{1083\pi }{32}-\cfrac{1125\pi }{32}\implies \cfrac{85\pi }{4}\quad \approx\quad 66.75884$

7 0

3 years ago

Angle rqs and tqs are linear pair where angle rqs equal 2x+4 and angle tqs equal 6x+20 solve for x

Ulleksa [173]

The answer is x = -2 you move the all x to one side and all numbers to the other side. then divide to find x

8 0

3 years ago