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3 years ago

Write the equation that describes the line with slope = 4 and y-intercept = -2 in slope-intercept form.

Mathematics

1 answer:

JulsSmile [24]3 years ago

7 0

Answer:

2 66

Step-by-step explanation:

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5. Bob the Burrito is tumbling down a mountain, If Bob is going 20 m/s for 45 seconds

damaskus [11]

Answer: 0.444444444 m / s2

Step-by-step explanation: All you have to do is divide 20 m/s by 45 seconds and you get the answer.

Hope this helps!

I am joyous to assist anytime! (-:

~Jarvis

8 0

3 years ago

3( m - 1) = 5m +3 - 2m Solve pls

gizmo_the_mogwai [7]

Answer:

it's something like 6 or m=6

Step-by-step explanation:

8 0

3 years ago

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There are five different routes that a commuter can take from her home to the office. In how many ways can she make a round trip

Lynna [10]

Answer: 120 ways

Step-by-step explanation:

Let's label the routes a, b, c, d, and e. The goal is to come up with as many unique permutations as possible.

1 route: a=1. one factorial (1!) =1*1=1

2 routes: ab, ba=2. 2!=1*2=2

3 routes: abc, acb, bac, bca, cab, cba=6. 3!=1*2*3=6

4 routes: 4!=1*2*3*4=24

5 routes: 5!=1*2*3*4*5=120 ways

4 0

2 years ago

Use the Rational Zeros Theorem to write a list of all potential rational zeros. (5 points)

yawa3891 [41]

So the Rational Zeros Theorem states that the potential zeros are ± P/Q, with P = factors of the constant and Q = factors of the leading coefficient.

In this case, the constant is -3 and the leading coefficient is 2.

P = 1,3
Q = 1,2

With P and Q established, divide them all as such:

$\pm \frac{1}{1}, \pm \frac{3}{1}, \pm \frac{1}{2}, \pm \frac{3}{2}\\\\\pm 1,\pm 3, \pm \frac{1}{2}, \pm \frac{3}{2}$

In short, your potential zeros are ± 1/2, ± 3/2, ± 1, and ± 2.

4 0

3 years ago

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The measurement of the radius of the end of a log is found to be 9 inches, with a possible error of 1/2 inch. Use differentials

enot [183]

Answer:

$\pm 9in^2$

Step-by-step explanation:

We are given that

Radius of end of a log, r= 9 in

Error, $\Delta r=\pm 1/2$ in

We have to find the error in computing the area of the end of the log by using differential.

Area of end of the log, A= $pi r^2$

$\frac{dA}{dr}=2\pi r$

$\frac{dA}{dr}=2\pi (9)=18\pi in^2$

Now,

Approximate error in area

$dA=\frac{dA}{dr}(\Delta r)$

Using the values

$dA=18\pi (\pm 1/2)$

$\Delta A\approx dA=\pm 9in^2$

Hence, the possible propagated error in computing the area of the end of the log $=\pm 9in^2$

6 0

3 years ago

Read 2 more answers