Let
Present age of Sana = s
Present age of Mona = m
Sana is senior to Mona by 18 years
s=m+18............(1)
After 6 years
Sana will be = s+6
Mona will be = m+6
Then
Sana will be twice as old as Mona
(s+6)=2(m+6)
s+6=2m+12
s=2m+12-6
s=2m+6.............(2)
Put the value of s from (2) to (1)
2m+6=m+18
2m-m=18-6
m=12
Put the value of m in (1)
s=m+18
s=12+18
s=30
Present age of Sana = s = 30 years old
Present age of Mona = m = 12 years old
<span>8w^3 + 12w^2 + 10w +15
Take each two terms and find common factors for each:
4w^2(2w+3)+5(2w+3)
Group them together:
And that is your final answer:
(4w^2+5)(2w+3)
Hope this helps :)</span>
Answer:
100 oxygen molecules simple math
81 pages.
Step-by-step explanation:
Tuesday: 3 x 3 = 9
Wednesday: 9 x 3 = 27
Thursday: 27 x 3 = 81