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3 years ago

BLK = (congruent) ACK

Mathematics

1 answer:

Evgen [1.6K]3 years ago

5 0

AAA

two alternate angle

one is vertically opposite angle

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Hey:) can you please help me posted picture of question

oee [108]

Answer:
x² + 10x + 25

Explanation:
Before we begin, remember the following:
(a + b)(a + b) = (a + b)² = a² + 2ab + b²

Now, for the given we have:
(x + 5)(x + 5)
We can note that the two brackets are identical.
Therefore, we can apply the above rule as follows:
(x + 5)(x + 5) = (x + 5)²
= (x)² + 2(x)(5) + (5)²
= x² + 10x + 25

Hope this helps :)

8 0

3 years ago

Solve following | 2x + 9 = 15

vivado [14]

Answer:

x₁ = 3

x₂ = - 12

Step-by-step explanation:

Hi there !

| 2x + 9 | = 15

1.

2x + 9 = 15

2x = 15 - 9

2x = 6

x = 6 : 2

x₁ = 3

2.

2x + 9 = - 15

2x = - 15 - 9

2x = - 24

x = - 24 : 2

x₂ = - 12

Good luck !

4 0

3 years ago

4 3/4 divided by 1 1/6

ozzi

Answer:

$2\frac{13}{22}$

Step-by-step explanation:

$=\frac{19}{4}\div \frac{11}{6}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{b}\div \frac{c}{d}=\frac{a}{b}\times \frac{d}{c}$

$=\frac{19}{4}\times \frac{6}{11}$

$=\frac{19}{2}\times \frac{3}{11}$

$\mathrm{Multiply\:fractions}:\quad \frac{a}{b}\times \frac{c}{d}=\frac{a\:\times \:c}{b\:\times \:d}$

$=\frac{19\times \:3}{2\times \:11}$

$\mathrm{Multiply\:the\:numbers:}\:19\times \:3=57$

$=\frac{57}{2\times \:11}$

$\mathrm{Multiply\:the\:numbers:}\:2\times \:11=22$

$=\frac{57}{22}$

$=2\frac{13}{22}$

5 0

2 years ago

A particular isotope has a half-life of 74 days. If you start with 1 kilogram of this isotope, how much will remain after 150

shtirl [24]

$\bf \stackrel{150~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &150\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{150}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{75}{37}}\implies \boxed{A\approx 0.24536}$

$\bf \stackrel{300~days}{\textit{Amount for Exponential Decay using Half-Life}} \\\\ A=P\left( \frac{1}{2} \right)^{\frac{t}{h}}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1\\ t=\textit{elapsed time}\dotfill &300\\ h=\textit{half-life}\dotfill &74 \end{cases} \\\\\\ A=1\left( \frac{1}{2} \right)^{\frac{300}{74}}\implies A=1\left( \frac{1}{2} \right)^{\frac{150}{37}}\implies \boxed{A\approx 0.060202}$

6 0

3 years ago

Jeremy is randomly selecting an outfit to celebrate Probability Day at his school. He can choose from a green (G) or purple (P)

asambeis [7]

C socks, and boots.
Because it could be cold outside?

6 0

2 years ago