All categories

3 years ago

The value of sqrt-9 is not -3 because

Mathematics

2 answers:

Umnica [9.8K]3 years ago

7 0

<u>Answer with explanation:</u>

The value of square -9 is not -3 ( $\sqrt { - 9 } \neq - 3$ ).

It is because we cannot take a square root of a negative number since any number multiplied by itself is a positive number so you never get a negative value.

Therefore, it given an error if you try to take a square root of a negative number on a calculator.

fenix001 [56]3 years ago

5 0

Answer:

The value of √-9 is not -3 because we cannot take the square root of negative numbers

Step-by-step explanation:

It is not possible to take square root of a negative number.

If any positive number we can take its square roots.

-9 is a negative number.

√9 = ±3 means that,

√9 = 3 or √9 = -3

3 * 3 = 9 and -3 * -3 = 9

Therefore the value of √-9 is not -3

You might be interested in

Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)

UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600$

Therefore, the probability is

$P=\frac{12117600}{53524680}\\\\P=0.226$

b) We calculate the probability that are at least 2 red balls.

We calculate the probability withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations: for 1 red balls

$C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848$

Therefore, the probability is

$P_1=\frac{16138848}{53524680}\\\\P_1=0.3$

We calculate the number of favorable combinations: for none red balls

$C_7^{34}=5379616$

Therefore, the probability is

$P_0=\frac{5379616}{53524680}\\\\P_0=0.1$

Therefore, the the probability that are at least 2 red balls is

$P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6$

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056$

Therefore, the probability is

$P=\frac{44056}{53524680}\\\\P=0.0008$

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

$P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\$

Let Y, event that exactly 3 blue balls selected.

$P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\$

We have

$P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12$

Therefore, we get

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74$

8 0

3 years ago

Zelda bought a blouse and a sweater for a total price of $79. The price of the sweater was $4 more than twice the price of the b

Bogdan [553]

A correct possibility could be $37.50 because 37.50 x 2 + 4 = 79

6 0

3 years ago

How to find the shaded region of a circle with a rectangle inside?

WINSTONCH [101]

You would start by finding the area of the circle and then finding the area of the rectangle. After finding both, subtract the area of the rectangle from that of the circle. <span />

8 0

3 years ago

Identify the percent of change as an increase or a decrease 3/8 to 7/8

irinina [24]

Answer:no

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

684303 rounded to nearest thousand

horsena [70]

684,000. This should give you the correct answer as the 4 is the thousands place. Good luck :D

3 0

3 years ago