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3 years ago

8

How is the water molecule different from the oxygen and hydrogen molecules

1 answer:

klemol [59]3 years ago

4 0

In a water molecule<span>, the </span>oxygen<span> atom and </span>hydrogen<span> atoms share electrons in covalent bonds, but the sharing isn't equal. ... The unequal sharing of electrons gives the </span>water molecule<span> a little bit of a negative charge near its </span>oxygen<span> atom and a slight positive charge near its </span>hydrogen<span> atoms.</span>

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Tim and Mike share $55.32 in the ration 7∶5 respectively. How much does Mike receive? pls pls pls don't scam me

VLD [36.1K]

Answer:

£11.064

Step-by-step explanation:

55.32/5 = 11.064

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3 years ago

-4x+1=2x-17 What is the solution for x ?

katovenus [111]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{x = 3}}}}}$

Step-by-step explanation:

$\sf{ - 4x + 1 = 2x - 17}$

Move 2x to left hand side and change it's sign

Similarly, move 1 to right hand side and change it's sign

$\dashrightarrow{ \sf{ - 4x - 2x = - 17 - 1}}$

Collect like terms

$\dashrightarrow{ \sf{ - 6x = - 17 - 1}}$

The negative integers are always added but posses the negative ( - ) sign

$\dashrightarrow{ \sf{ - 6x = - 18}}$

Divide both sides by -6

$\dashrightarrow{ \sf{ \frac{ - 6x}{ - 6} = \frac{ - 18}{ - 6}}}$

Calculate

$\dashrightarrow{ \sf{x = 3}}$

Hope I helped!

Best regards! :D

6 0

3 years ago

Thanks for any help. i’ll give 5 stars and thanks.

Alex

Answer:

140

Step-by-step explanation:

cus i said so

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2 years ago

(tan theta+ cot theta)^2= sec^2 theta+cosec^2 theta

Virty [35]

Answer:

Proved that $(\tan \theta + \cot \theta)^{2} = \sec^{2} \theta + \csc^{2} \theta$ .

Step-by-step explanation:

We have to prove that

$(\tan \theta + \cot \theta)^{2} = \sec^{2} \theta + \csc^{2} \theta$

Now, Left hand side

= $(\tan \theta + \cot \theta)^{2}$

= $\tan^{2} \theta + 2\times \tan \theta \times \cot \theta + \cot^{2} \theta$ {Since we know the formula (a + b)² = a² + 2ab + b²}

= $\tan^{2} \theta + 2 + \cot^{2} \theta$

{Since $\tan \theta \times \cot \theta = 1$ }

= $(\tan^{2} \theta + 1) + (\cot^{2} \theta + 1)$

= $\sec^{2} \theta + \csc^{2} \theta$

{Since we know the identities:

$\sec^{2} x = \tan^{2} x + 1$ and $\csc^{2} x = \cot^{2} x + 1$ }

= Right hand side

Hence, proved.

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3 years ago

Four adults are going on a 13 hour road trip. How long should each person drive if all four adults share the driving time equall

Doss [256]

Answer:

3hr. and 15min. each : )

Step-by-step explanation: Thank me for intelectual skills even if im wrong... Im very wise

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3 years ago