The figure shows two triangles on the coordinate grid: A coordinate grid is shown from positive 6 to negative 6 on the x-axis an
d from positive 6 to negative 6 on the y-axis. A triangle ABC is shown with vertex A on ordered pair 4, 1, vertex B on ordered pair 3, 1, and vertex C on ordered pair 4, 4. Another triangle A prime B prime C prime is shown with vertex A prime on ordered pair negative 4, 4, vertex B prime on ordered pair negative 3, 4, and vertex C prime on ordered pair negative 3, 1. What set of transformations is performed on triangle ABC to form triangle A'B'C'? A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin A translation 5 units down, followed by a 270-degree counterclockwise rotation about the origin A 180-degree counterclockwise rotation about the origin, followed by a translation 5 units down A 270-degree counterclockwise rotation about the origin, followed by a translation 5 units down
2 answers:
Check the picture.
since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.
The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.
We see that the distance CC'' is 5.
So
Answer is:
"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"
since the choices all have rotation about the origin, we must shift the original triangle in a suitable position. This is done by connecting any of the points of A'B'C' to the origin, and extend this line segment, as shown in the picture.
The most appropriate point is C', and we draw C" such that C'O=OC", and C', O and C" are collinear.
We see that the distance CC'' is 5.
So
Answer is:
"<span>A translation 5 units down, followed by a 180-degree counterclockwise rotation about the origin</span>"
You might be interested in
73.
a)
b)
Since we can't divide by zero, we need to find when:
But before, we can factor the numerator and the denominator:
Now, we can conclude that the vertical asymptotes are located at:
so, for x = -3:
For x = 4: