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3 years ago

What is 60 times 20 plz answer and make it quick!!

Mathematics

2 answers:

timurjin [86]3 years ago

6 0

1200 hope this helps u

Veronika [31]3 years ago

4 0

60 × 20= 1200

This time there are 2 methods:

1st method: Pretend that both zeros are gone and you are left with 6 × 2= 12
Then you could just add the 2 zeros that you pretended that were gone.

2nd method: If you want to show work:

60
x
20
------
000
+
120
--------
1200

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Which property is demonstrated <br> 9 * 3 * 4 = 4 * 3 * 9

mr_godi [17]

The commutative property of multiplication.

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3 years ago

Solve for the roots in the equation below. In your final answer, include each of the necessary steps and calculations.

Nostrana [21]

$x^3-27i=0$
$x^3=27i$
$x^3=27e^{i\pi/2}$
$x=\left(27e^{i\pi/2}\right)^{1/3}$
$x=3e^{i(\pi/2+2\pi k)/3}$
$x=3e^{i\pi(4k+1)/6}$

where $k\in\{0,1,2\}$ . This means you have

$x=3e^{i\pi/6}=\dfrac32(\sqrt3+i)$
$x=3e^{i5\pi/6}=\dfrac32(-\sqrt3+i)$
$x=3e^{i9\pi/6}=-3i$

as the solutions to the original equation.

4 0

3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

Read more about the center of mass.

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8 0

2 years ago

Work out the answers to <br>a) 7 × (-4)<br>b) (-6) × 8<br>c) (-5) x (-9)

kow [346]

A)-28
B)-48
C)45
Hope this helps :)

6 0

3 years ago

Simplify.<br><br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B8%2B6%5E2%7D%7B11%7D%20" id="TexFormula1" title=" \frac{8+6^2}{

Romashka [77]

$\frac{8 + 6^2}{11} + 7 \times 2 \\ \\ \frac{8 + 36}{11} + 7 \times 2 \ / \ simplify \\ \\ \frac{44}{11} + 7 \times 2 \ / \ simplify \\ \\ 4 + 7 \times 2 \ / \ simplify \\ \\ 4 + 14 \ / \ simplify \\ \\ 18 \ / \ simplify \\ \\$

The final result is 18.

4 0

3 years ago