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adoni [48]
3 years ago
9

What is 60 times 20 plz answer and make it quick!!

Mathematics
2 answers:
timurjin [86]3 years ago
6 0
1200 hope this helps u
Veronika [31]3 years ago
4 0
60 × 20= 1200

This time there are 2 methods:

1st method: Pretend that both zeros are gone and you are left with 6 × 2= 12
Then you could just add the 2 zeros that you pretended that were gone.

2nd method: If you want to show work:

 60
 x
 20
------
 000
+
120
--------
1200
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Please help me with 1 & 3!
kiruha [24]
On three does it tells you the data
7 0
3 years ago
Read 2 more answers
L33. Solve 41x - 7 + 12 = 28<br> Solution(s).
s2008m [1.1K]

Answer:

41x-7+12=28

41x+5=28

41x=28-5

41x= 23

x= 23/41

x= 0.56

7 0
2 years ago
A cube with side length mmm has a volume of 343343343 cubic centimeters. The following equation shows the volume of the cube.
MatroZZZ [7]

Answer:7cm

Step-by-step explanation:

m^3=343

Take the cube root of both sides

m=7

6 0
3 years ago
A human resources representative claims that the proportion of employees earning more than $50,000 is less than 40%. To test thi
bearhunter [10]

Answer:

The statistic for this case would be:

z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}

And replacing we got:

z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92

Step-by-step explanation:

For this case we have the following info:

n =700 represent the sample size

X= 305 represent the number of employees that earn more than 50000

\hat p=\frac{305}{700}= 0.436

We want to test the following hypothesis:

Nul hyp. p \leq 0.4

Alternative hyp : p>0.4

The statistic for this case would be:

z=\frac{\hat p -p_o}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}

And replacing we got:

z= \frac{0.436-0.4}{\sqrt{\frac{0.436*(1-0.436)}{700}}}= 1.92

And the p value would be given by:

p_v = P(z>1.922)= 0.0274

4 0
3 years ago
An exam worth 148 points contains 36 questions. Some questions are worth 2 points, and the others are worth 6 points. How many 2
Airida [17]

In order to solve for this question, let's assign a couple variables.

The variable 't' will represent the number of two-point questions, and the variable 's' will represent the number of six point questions.

From the given, we can already form two equations:

t + s = 36

("An exam... contains 36 questions")

2t + 6s = 148

("An exam worth 148 points... Some questions are worth 2 points, and the others are worth 6 points")

Before we begin calculating anything, we can simplify the second equation we made, since all the numbers are divisible by 2:

2t + 6s = 148

t + 3s = 74

Now let's refer back to the first equation. We can subtract both sides by 's' (you could also subtract both sides by 't', but I personally think that this will make solving the equation less difficult):

t + s = 36

t = 36 - s

This effectively gives us a value for the variable 't'. We can assign this value back into our first equation:

t + 3s = 74

(36 - s) + 3s = 74

36 + 2s = 74

2s = 38

s = 19

Input 's' into our second equation to solve for 't':

t = 36 - s

t = 36 - 19

t = 17

There are 17 two-point questions and 19 six-point questions

- T.B.

4 0
3 years ago
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