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3 years ago

Which fraction is represented by point A on the number line?

Mathematics

1 answer:

Akimi4 [234]3 years ago

7 0

This would be a lot easier with the figure.

Four equal spaces means quarters.

A is 1 mark to the left of 0, so 1/4 to the left of 0. That's -1/4

Answer: Negative one-fourth

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(-x²+9) + (-3x²-11x+4)

Maslowich

Answer:

=-4x^2-11x+13

Step-by-step explanation:

6 0

3 years ago

Please answer the questions before 12 am

Delvig [45]

Answer:

Step-by-step explanation:

42)1.50/6=0.25

43)3/2=1.5

44)1x2=2

5 0

3 years ago

Read 2 more answers

In 1850, a person sold a house to a lady for $30. If the lady had put the $30 into a bank account paying 4% interest, how much w

jekas [21]

30$ profit each person of connect

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3 years ago

A backyard measures 30 feet by 40 feet. If the owner builds a fence around, about how many feet of fencing will be needed?

Troyanec [42]

Answer:

140 feet

Step-by-step explanation:

You will need to find the perimeter of the backyard to find how many feet of fencing will be needed

the formula for perimeter is: 2l+2w

So 2 times 30 is 60

with 2 times 40 80

60+80 is 140

Thus you will need 140 feet to cover the backyard

Hope this helps!

8 0

2 years ago

Read 2 more answers

A large tank is filled to capacity with 600 gallons of pure water. brine containing 4 pounds of salt per gallon is pumped into t

nignag [31]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which the amount of salt in the tank changes is given by

$\dfrac{\mathrm dA(t)}{\mathrm dt}=\dfrac{4\text{ lbs}}{1\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}-\dfrac{A(t)\text{ lbs}}{600\text{ gal}}\dfrac{6\text{ gal}}{1\text{ min}}$
$\dfrac{\mathrm dA}{\mathrm dt}=24\dfrac{\text{lb}}{\text{min}}-\dfrac{A(t)}{100}\dfrac{\text{lb}}{\text{min}}$

Let's drop the units for now. We have

$\dfrac{\mathrm dA(t)}{\mathrm dt}+\dfrac{A(t)}{100}=24$
$e^{t/100}\dfrac{\mathrm dA(t)}{\mathrm dt}+e^{t/100}\dfrac{A(t)}{100}=24e^{t/100}$
$\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/100}A(t)\right]=24e^{t/100}$
$e^{t/100}A(t)=\displaystyle24\int e^{t/100}\,\mathrm dt$
$e^{t/100}A(t)=2400e^{t/100}+C$
$A(t)=2400+Ce^{-t/100}$

We're given that the water is pure at the start, so $A(0)=0$ , giving

$A(0)=0=2400+Ce^{-0/100}\implies C=-2400$

So the amount of salt in the tank (in lbs) at time $t$ is

$A(t)=2400\left(1-e^{-t/100}\right)$

4 0

3 years ago