The slope of the graph of the function is equal to 0 for x between x = -3 and x = -2.
The slope of the graph of the function is equal to 0 for x between x = 3 and x = 4.
The greatest value of y is y = 4.
The smallest value of y is y = -3.

<h3>How to complete the sentences?</h3>

By critically observing the graph shown in the image attached below, we can logically deduce that the slope of the graph of this function is equal to 0 for x, between x = -3 and x = -2.

Similarly, the slope of the graph of this function is also equal to 0 for x, between x = 3 and x = 4.

Based on the graph (see attachment), the greatest value of y is 4 while the smallest value of y is -3.

Read more on slope here: brainly.com/question/3493733

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4 0

1 year ago

The expression x+8x+10 is modeled below

adoni [48]

Answer:

add 6 unit tiles

Step-by-step explanation:

The square is completed when the algebra tile grid pattern is a square. This one will be a square when 6 more unit tiles are added to fill the empty spaces at the bottom right.

3 0

2 years ago

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Helppp meeeeeeeeeeeeeeee

postnew [5]

Answer:

Area = 168m^2

Step-by-step explanation:

Area of triangle = 1/2×base×height

Area = 1/2bh

= 1/2(8+16)(14)

= 168m^2

7 0

2 years ago

What is the solution set to the inequality

creativ13 [48]

$(4x - 3)(2x - 1) \geqslant 0 \\ \Leftrightarrow \begin{cases}4x - 3 \geqslant 0 \\ 2x - 1 \geqslant 0\end{cases}\: \vee \:\begin{cases}4x - 3 \leqslant 0 \\2x - 1 \leqslant 0 \end{cases} \\ \Leftrightarrow \begin{cases}x \geqslant \frac{3}{4} \\ x \geqslant \frac{1}{2} \end{cases}\: \vee \:\begin{cases}x\leqslant \frac{3}{4} \\x \leqslant \frac{1}{2} \end{cases} \\ \Leftrightarrow x \geqslant \frac{3}{4} \: \vee \: x \leqslant \frac{1}{2} \\ \Rightarrow The\: third\: option$

5 0

2 years ago

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