Answer:
The width of the interval would increase.
Step-by-step explanation:
Answer:
Step-by-step explanation:
![\int\bigg(x(x-6)^3\bigg)dx\Rightarrow\left[\begin{array}{ccc}x-6=u\\x=u+6\\dx=du\end{array}\right]\Rightarrow\int\bigg((u+6)u^3\bigg)du\\\\=\int(u^4+6u^3)du=\dfrac{1}{5}u^5+\dfrac{6}{4}u^4+C=\dfrac{1}{5}(x-6)^5+\dfrac{3}{2}(x-6)^4+C](https://tex.z-dn.net/?f=%5Cint%5Cbigg%28x%28x-6%29%5E3%5Cbigg%29dx%5CRightarrow%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Dx-6%3Du%5C%5Cx%3Du%2B6%5C%5Cdx%3Ddu%5Cend%7Barray%7D%5Cright%5D%5CRightarrow%5Cint%5Cbigg%28%28u%2B6%29u%5E3%5Cbigg%29du%5C%5C%5C%5C%3D%5Cint%28u%5E4%2B6u%5E3%29du%3D%5Cdfrac%7B1%7D%7B5%7Du%5E5%2B%5Cdfrac%7B6%7D%7B4%7Du%5E4%2BC%3D%5Cdfrac%7B1%7D%7B5%7D%28x-6%29%5E5%2B%5Cdfrac%7B3%7D%7B2%7D%28x-6%29%5E4%2BC)
First, you have to make a Y axis and an X axis. Classes go on the Y axis ( going up and down) and frequency goes on the x axis ( going across) then you graph (in bars) the amount of tallys that match to the amount of frequency. Do u get it? comment if u need more detail:)
Answer:
Find the area land of each town.
Let x be the area of town D
then, x+ 30000 is the area of town C
we know that,
the total area of town C and town D is 120,000 square miles.
x+x+30000=120000
2x= 90000
x=45000
Area of town D= 45000 square miles
Area of town C= 45000+30000= 75000 square miles.
Answer:
C
Step-by-step explanation:
