All categories

3 years ago

Which represents the solution set of 5(x+5)<85

1 answer:

8 0

Simple...

you have: 5(x+5)<85

Simplify it-->>(Distribute the 5)

5(x+5)<85

5x+25<85

5x+25<85
-25 -25

5x<60

x<12

Thus, your answer.

You might be interested in

PLEASE ANSWERRRRRRRRRR

Alecsey [184]

Answer:

True

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

A scale model of a rectangular building lot measures 7 feet by 5 feet. If the actual house will be built using a scale factor of

eimsori [14]

Answer:

<em>The area of the actual building lot is</em> $5,040\ ft^2$

Step-by-step explanation:

<u>Scaling</u>

The scaled rectangular building measures 7 feet by 5 feet. We know both magnitudes were scaled by a factor of 12, thus the real dimensions of the house to be built are 7*12=84 feet, and 5*12=60 feet.

The area of the actual building lot is calculated by:

$A=84\ ft*60\ ft=5,040\ ft^2$

The area of the actual building lot is $5,040\ ft^2$

4 0

3 years ago

Idk what to put here lol

Sav [38]

Answer:72

Step-by-step explanation:

The big one is 4 times the small one

6 0

3 years ago

What's the slope of 4x-5y+20=0

expeople1 [14]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find the value of the line integral. F · dr C (Hint: If F is conservative, the integration may be easier on an alternative path.

Harman [31]

Answer: a) Fdr = 0 b) Fdr = 0

Step-by-step explanation:

According to the integral Fdr

a) If r=t²i + t²j

If the field F(x, y, z) = y sin(z)i + x sin(z)j + xy cos(x)k

Integral Fdr = y sin(z)i + x sin(z)j + xy cos(x)k d(t²i + t²j)

Multiplying component wise.

Fdr = y sin(z)i(dt²i) + x sin(z)j(dt²j) + xy cos(x)k d(0k)

Remember that dot product of different components gives 'zero' i.e i.j = 0 etc.

Fdr = ysin(z)dt² + xsin(z)dt² + 0...(1)

Generally for 2dimensional object r=xi+yj

Comparing this to r = t²i+t²j

x=t² and y = t² z = 0...(2)

Substituting 2 into 1

Fdr = t²sin0dt² + t²sin0dt²

Integrating resulting Fdr with respect to t² within the limit 0 ≤ t ≤ 2, we have

Fdr = 0

b) since there is no z-component in the second part as well, integral of Fdr within the limit 0 ≤ t ≤ 1 will also be 0.

3 0

3 years ago