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lukranit [14]
3 years ago
7

Use the formula A=bh , where A is the area, b is the base length, and h is the height of the parallelogram, to solve this proble

m. A sign on the side of a van is in the shape of a parallelogram. The area of the sign is 330 square inches. The base of the sign is 22 inches long. What is the height of the sign?
Enter your answer in the box.

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Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0
I think the height is 15/or 16
lidiya [134]3 years ago
5 0
The height of this specific sign is 15 inches. 
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What could this answer be??
bekas [8.4K]

The number in the parentheses is the rate of change. Because this number is less than 1 it is a decrease, so it is a decay.

The percent decrease is 1 - 0.63 = 0.37 = 37% decrease

5 0
3 years ago
Express the illuminance on the floor as a composite function of t for 0 < t < 8.
GrogVix [38]
The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t

The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²

The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
3 0
3 years ago
Multiple the binomials (x+3)^2
maxonik [38]

Answer:

=x^2+6x+9

Step-by-step explanation:

\left(x+3\right)^2\\\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2\\a=x,\:\:b=3\\=x^2+2x\cdot \:3+3^2\\\mathrm{Simplify}\:x^2+2x\cdot \:3+3^2:\quad x^2+6x+9\\x^2+2x\cdot \:3+3^2\\\mathrm{Multiply\:the\:num\\bers:}\:2\cdot \:3=6\\=x^2+6x+3^2\\3^2=9\\=x^2+6x+9

8 0
3 years ago
Idk how to do my hw
solniwko [45]

What is your homework?

8 0
3 years ago
Read 2 more answers
The vertical asymptote of the function f(x) = 3 log(x + 3)
ipn [44]

A function has a vertical asymptote where it is not defined, and the logarithm is defined only if its argument is strictly positive: it has a vertical asymptote if its argument is zero, and is not defined if its argument is negative.

So, you have a vertical asymptote where

x+3=0 \iff x=-3

4 0
3 years ago
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