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PtichkaEL [24]
2 years ago
9

The lengths of two sides of a right triangle are 12 inches and 15 inches. What is the difference between the two possible length

s of the third side of the triangle? Round your answer to the nearest tenth.
Mathematics
1 answer:
Anit [1.1K]2 years ago
6 0
I get 10.2 for this answer
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2x+15x you can just switch the two.
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In one year a dog’s weight increased from 64 to 80. By what percentage did the dogs weight increase?
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Solve for v.<br><br> 9v – v = 8
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Find the missing side length of the triangle 10m 7.5m
xxTIMURxx [149]

Answer:

c = 12.5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Trigonometry</u>

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

  • a is a leg
  • b is another leg
  • c is the hypotenuse<u> </u>

Step-by-step explanation:

<u>Step 1: Identify</u>

Leg <em>a</em> = 7.5

Leg <em>b</em> = 10

Hypotenuse <em>c</em> = <em>c</em>

<em />

<u>Step 2: Solve for </u><em><u>c</u></em>

  1. Substitute in variables [Pythagorean Theorem]:                                              7.5² + 10² = c²
  2. Rewrite:                                                                                                             c² = 7.5² + 10²
  3. Evaluate exponents:                                                                                         c² = 56.25 + 100
  4. Add:                                                                                                                   c² = 156.25
  5. [Equality Property] Square root both sides:                                                    c = 12.5
5 0
3 years ago
I need help for these fraction questions! I will give brainleist! Please!!
Zina [86]
So it seems as if the first problem is asking this:

2 \frac{1}{6} - \frac{11}{15}x. 

If x=0.15, then 11/15*(0.15) is 0.11 or 11/100. 

The second problem is asking:

\frac{x}{4} + \frac{1}{2} = \frac{x}{3} + \frac{1}{6}

To solve algebraically, you want to get rid of the denominators under the x's. To do so, you want to multiply by the Least Common Multiple (LCM) of the denominators. For 3 and 4, the LCM is 12. Multiply everything by 12 to get:

3x+6=4x+2

Now, solve for x

Subtract 4x from both sides:
-x+6=2

Subtract 6 from both sides:
-x=-4

Multiply by -1 on both sides:
x=4. 

8 0
3 years ago
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