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Amiraneli [1.4K]
3 years ago
13

Vladimir says that the equation of the line that passes through points (negative 5, negative 3) and (10, 9) is y = four-fifths x

+ 1. Robyn says that the line passes through the points (negative 10, negative 7) and (negative 15, negative 11). Who is correct?
Mathematics
2 answers:
love history [14]3 years ago
4 0

Answer:

Vladimir and Robyn both are correct.

Step-by-step explanation:

Let us check whether the points (-5,-3) and (10,9) are on the line y = \frac{4}{5}x + 1 or not.

The equation of the straight line passing through the given points (-5,-3) ans (10,9) is \frac{y - 9}{9 + 3} = \frac{x - 10}{10 + 5}

⇒ 5(y - 9) = 4(x - 10)

⇒ 5y = 4x + 5

⇒  y = \frac{4}{5}x + 1 .............. (1)

So, Vladimir is correct.

Now, Robyn says that the line passes through the points (-10,-7) and (-15,-11).

Then, both of the points satisfy the equation (1).

Therefore, Vladimir and Robyn both are correct. (Answer)

valentinak56 [21]3 years ago
4 0

Answer:

Step-by-step explanation:

(10, 9) is y = four-fifths x + 1. Robyn says that the line passes through the points (negative 10, negative 7) and (negative 15, negative 11).

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nadezda [96]
I think you are right so far what i've done comes out to your answer.
6 0
3 years ago
Help me out plesseee!!
nasty-shy [4]

Step-by-step explanation:

the rate of change is officially

(f(x2) - f(x1)) / (x2 - x1)

but for a line function (as we have here) this is totally easy : it is the slope of the line.

and that means it is the factor of x.

in our case this is -3/2.

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3 0
2 years ago
>
kondor19780726 [428]

Answer:

23 degrees

Step-by-step explanation:

Find the diagram attached

The sum of angle on the straight line is 180°

103+3x+15+x+10 = 180

128+4x =180

4x = 180-128

4x = 52

x = 52/4

x = 13

The measure of the angle of the intersection between Derby Drive and Rosemont is x+10

= 13+10

= 23 degrees

Hence the measure of the angle is 23 degrees

5 0
3 years ago
Can someone solve this?
aleksley [76]

Answer:

Considering the Law of Cosines:

c^2=a^2+b^2-2ab*cosC

a=14mi; b=24mi; c=CA; C=91degrees

\cos \left(91^{\circ \:}\right)=-0.01745\dots

c^2=14^2+24^2-2(14)(24)*\cos \left(91^{\circ \:}\right)\\c^2=196+576-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*\cos \left(91^{\circ \:}\right)\\c^2=772-672*(-0.01745)\\c^2=772+11.7264\\c=\sqrt{772+11.7264} \\c=\sqrt{783.7264}\\c=27.99mi

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3 years ago
Some help would be appreciated
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She was driving an average of 51 mph.
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