Plsss i need answer for this

Mathematics

1 answer:

Rashid [163]3 years ago

6 0

Step-by-step explanation:

1. 5 divided 4 times of a number n.

2. 3 subtracted by a number B gives 13.

3. 39 added by a number m divided by 7. (not sure)

4. m divided by 90 gives 15.

5. 32 subtracted by two times of a number N.

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Simplify the problem 2/sqrt 5

AURORKA [14]

2/sqrt 5

by rationalising the denominator,

2/sqrt 5 × sqrt 5/sqrt 5

= 2(sqrt 5)/sqrt 5(sqrt 5)

= 2 sqrt 5/5

-

hope this helps! :))))

7 0

3 years ago

Plz help I'm really bad at these

GREYUIT [131]

Y = mx + b, where m = slope = rise/run and b, the y intercept value

m = 1/1 = 1, then y = x + b.
We notice that y intercept is = - 1
And the equation is:

y = x - 1

6 0

3 years ago

A ball is thrown from a height of 38 meters with an initial downward velocity of 3 m/s

ANTONII [103]

<h2>Hello!</h2>

The answer is:

The ball will hit the ground after $t=2.47s$

Since we are given a quadratic function, we can calculate the roots (zeroes) using the quadratic formula. We must take into consideration that we are talking about time, it means that we should only consider positive values.

So,

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

We are given the function:

$h=-5t^{2}-3t+38$

Where,

$a=-5\\b=-3\\c=38$

Then, substituting it into the quadratic equation, we have:

$\frac{-b+-\sqrt{b^{2} -4ac} }{2a}=\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}\\\\\frac{-(-3)+-\sqrt{(-3)^{2} -4*-5*38} }{2*-5}=\frac{3+-\sqrt{9+760} }{-10}\\\\\frac{3+-\sqrt{9+760} }{-10}=\frac{3+-\sqrt{769} }{-10}=\frac{3+-27.731}{-10}\\\\t1=\frac{3+27.731}{-10}=-3.073s\\\\t2=\frac{3-27.731}{-10}=2.473s$