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ElenaW [278]
3 years ago
10

the members of the boosters organization at your high school bought new balls for the school. they spent $22.00 per basketball a

nd $30.00 per football, spending a total of $648.00. They bought 6 more footballs than basketballs. How many of each type of ball did they buy?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
3 0

Answer:

9 basket balls, 15 foot balls

Step-by-step explanation:

Let x be the number of basket ball

y be the number of foot ball

1 basket ball = $22

so x basket ball = 22x

1 foot ball = $30

so y foot ball = 30y

Total cost = 648

The equation becomes 22x+ 30y = 648

Given : They bought 6 more footballs than basketballs.

foot  ball (y) = 6 more basket balls(x)

so y = x + 6

we solve for  x  and y

Now we plug in x+6 for y in the equation 22x+ 30y = 648

22x+ 30(x+6) = 648

22x + 30x + 180 = 648

Subtract 180 on both sides

52x = 468

Divide both sides by 52

so x= 9

Number of basket ball x= 9

Number of foot ball y=x+6= 9+ 6 = 15




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Answer:

0.99 probability that at least one trip will last less than an hour

Step-by-step explanation:

For each time that the machine is used, there are only two possible outcomes. Either it lasts more than an hour, or it does not. The probability of a trip lasting more than an hour is independent of other trips. So the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

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We want P(X < 20). So

P(X < 20) = 1 - P(X = 20)

In which

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P(X = 20) = C_{20,20}.(0.8)^{20}.(0.2)^{0} = 0.0115

P(X < 20) = 1 - P(X = 20) = 1 - 0.0115 = 0.9885

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Rouding to the nearest hundreth.

0.99 probability that at least one trip will last less than an hour

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