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ElenaW [278]
3 years ago
10

the members of the boosters organization at your high school bought new balls for the school. they spent $22.00 per basketball a

nd $30.00 per football, spending a total of $648.00. They bought 6 more footballs than basketballs. How many of each type of ball did they buy?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
3 0

Answer:

9 basket balls, 15 foot balls

Step-by-step explanation:

Let x be the number of basket ball

y be the number of foot ball

1 basket ball = $22

so x basket ball = 22x

1 foot ball = $30

so y foot ball = 30y

Total cost = 648

The equation becomes 22x+ 30y = 648

Given : They bought 6 more footballs than basketballs.

foot  ball (y) = 6 more basket balls(x)

so y = x + 6

we solve for  x  and y

Now we plug in x+6 for y in the equation 22x+ 30y = 648

22x+ 30(x+6) = 648

22x + 30x + 180 = 648

Subtract 180 on both sides

52x = 468

Divide both sides by 52

so x= 9

Number of basket ball x= 9

Number of foot ball y=x+6= 9+ 6 = 15




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Answer:

<em>She will be paid $1,350</em>

Step-by-step explanation:

<u>Linear Modeling</u>

Some events can be modeled as linear functions. If we are in a situation where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

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The payments for a salesperson will be linearly modeled. There are two known points: When the sales were $16,000, the payment was $1,600. This makes the point (16,000;1,600).

We also know when the sales were $12,000, the payment was $1,400. The point is (12,000;1,400)

Let's use the points to find the values of m and b.

Using (16,000;1,600):

1,600=m*16,000+b

Using (12,000;1,400):

1,400=m*12,000+b

Subtracting both equations:

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Solving:

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Using the first equation and the value of m:

1,600=0.05*16,000+b

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Solving:

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The equation is now complete:

y=0.05x+800

She sold $11,000 this month, so the payment is:

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She will be paid $1,350

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