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3 years ago

Identify the reflection of the figure with vertices

Mathematics

1 answer:

aivan3 [116]3 years ago

3 0

Reflection across the x-axis:
the x coordinate will stay the same but y coordinate will change sign

for example ( 2, -4) will reflect to 2 , 4)

Check out option B

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(2x)x(5x^2)= I just needed to write more

prisoha [69]

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3 years ago

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4 years ago

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malfutka [58]

Answer:

Step-by-step explanation:

Using the cofunction identity

sin x = cos(90 - x)

Given

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3 years ago

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xxMikexx [17]

Answer:

The answer is 4 + √15 .

Step-by-step explanation:

You have to get rid of surds in the denorminator by multiplying it with the opposite sign :

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$= \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} }$

$= \frac{ {( \sqrt{5} + \sqrt{3} ) }^{2} }{( \sqrt{5} - \sqrt{3} )( \sqrt{5} + \sqrt{3}) }$

$= \frac{ {( \sqrt{5} )}^{2} + 2( \sqrt{5} )( \sqrt{3}) + {( \sqrt{3}) }^{2} }{ {( \sqrt{5}) }^{2} - { (\sqrt{3} )}^{2} }$

$= \frac{5 + 2 \sqrt{15} + 3 }{5 - 3}$

$= \frac{8 + 2 \sqrt{15} }{2}$

$= 4 + \sqrt{15}$

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3 years ago

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