3 years ago

For each multiple of 9, find the sum of the ones digit and the tens digit.

Mathematics

1 answer:

jek_recluse [69]3 years ago

3 0

Multiples of 9:

09 — 9
18 — 9
27 — 9
36 — 9
45 — 9
54 — 9
63 — 9
72 — 9
81 — 9
90 — 9

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b) $3.5 \times 10^{3}$

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= $(9 \times 5) \times (10^{3} \times 10^{7})$

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For each multiple of 9, find the sum of the ones digit and the tens digit.​

For each multiple of 9, find the sum of the ones digit and the tens digit.