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KATRIN_1 [288]
3 years ago
12

PLEASE HELP ME !!! THIS IS DUE TODAY AND IM STUCK ON IT!!! Pls❤️✨❤️

Computers and Technology
1 answer:
Georgia [21]3 years ago
4 0
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click attachment to see correct answer. Which agencies run the Landsat Program? The Landsat program is run by ___ and ___.​
Ksju [112]

Answer:

ancient times were nicr

Explanation:

5 0
2 years ago
ImmuneEarth, a research and development company, has "eradicate all diseases" as its motto. It has numerous departments that res
anastassius [24]

Answer:

Grid computing.

Explanation:

Grid computing is a study utilizing Immune Earth to test AIDS treatment because the following are the reasons that describe the answer is true about the scenario.

  • Grid computing seems to be a scattered network with a vast amount for systems linked to handle a difficult issue.
  • Systems can be linked straightly or through organized systems.

Other options are incorrect.

  • Green computing is not the correct answer according to the scenario because the usage of systems and its energy is socially safe and economically sustainable.
  • Trusted Computing is not the correct answer according to the scenario because it helps a part of information to show which os as well as program to be required to access this.
  • Edge computing is not the correct answer according to the scenario because it optimizes web apps as well as software programs while getting computation back to the information base.
4 0
3 years ago
1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Write a program that prompts the user to input a number. The program should then output the number and a message saying whether
Gala2k [10]

Answer:

Following is the program in C++ Language

#include <iostream> // header file

using namespace std; // namespace std

int main() // main method

{

   int n;  // variable declaration

   cout<<" Please enter the number :";

   cin>>n; // Read the number

   if(n>0) // check the condition when number is positive

   {

cout<<n<<endl<<"The number is Positive"; // Display number

   }

  else if(n<0) // check the condition when number is Negative

  {

cout<<n<<endl<<"The number is Negative";// Display number

  }

  else // check the condition when number is Zero

  {

cout<<n<<endl<<"The number is Zero";// Display number

  }

   return 0;

  }

Output:

Please enter the number:

64

The number is Positive

Explanation:

Following are the description of the program

  • Declared a variable "n" of int type.
  • Read the value of "n" by user.
  • Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
  • Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
  • Finally if both the above condition is fail it print the message " The number is Zero"

7 0
3 years ago
Create a view named MAJOR CUSTOMER. It consists of the customer number, name, bal. ance, credit limit, and rep number for every
Step2247 [10]

Answer:

Following are the solution to the given point:

Explanation:

The solution to this question is defined in the attached in the attached file.

5 0
3 years ago
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