Answer:
First Time Unique Visitor
Explanation:
I majored in
Wet brining is a technique for seasoning meat by soaking it in a salt solution before cooking. As a general guideline, soak the meat in a solution containing 1 cup of salt per gallon of water. The salt will remain in the meat after cooking, imparting taste, and the liquid will be boiled away.
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Answer:
OLTP(Online transaction processing) is the correct answer.
Explanation:
It is the database application that is used to catching the transection and that data or information which is related to the technology for the purpose of.
- Process that data and information which is related to the following rules of the business or company.
- It stores the data or information related to the online transaction.
- It also helps to modify the current data or information for the new data or information.
In this program, I am using the school-based grading system and the program should accept the subject and the number of students.
Program approach:-
- Using the necessary header file.
- Using the standard I/O namespace function.
- Define the main function.
- Declare the variable.
- Display enter obtain marks in 5 subjects.
- Return the value.
Program:-
//header file
#include<iostream>
//using namespace
using namespace std;
//main method
int main()
{
//declare variable
int j;
float mark, sum=0, a;
//display enter obtain marks in 5 subjects
cout<<"Enter Marks obtained in 5 Subjects: ";
for(j=0; j<5; j++)
{
cin>>mark;
sum = sum+mark;
}
a = sum/5;
//display grade
cout<<"\nGrade = ";
if(a>=91 && a<=100)
//display a1
cout<<"a1";
else if(a>=81 && a<91)
//display a2
cout<<"a2";
else if(a>=71 && a<81)
cout<<"b1";
else if(a>=61 && a<71)
cout<<"b2";
else if(a>=51 && a<61)
//display c1
cout<<"c1";
else if(a>=41 && a<51)
//display c2
cout<<"c2";
else if(a>=33 && a<41)
//display d
cout<<"d";
else if(a>=21 && a<33)
//display e1
cout<<"e1";
else if(a>=0 && a<21)
//display e2
cout<<"e2";
else
//display invalid
cout<<"Invalid!";
cout<<endl;
//return the value
return 0;
}
Learn more grading system
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Answer:
nothing
Explanation:
Because the return type of the function is void. void means does not return any thing.
The syntax of the function:
type name( argument_1, argument_2,......)
{
statement;
}
in the declaration the type define the return type of the function.
it can be int, float, double, char, void etc.
For example:
int count( int index);
the return type of above function is int. So, it return integer.
similarly,
void count(int index);
it return type is void. So, it does not return any thing.
