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3 years ago

Can anyone help me with this equation?

Mathematics

2 answers:

Mice21 [21]3 years ago

8 0

liraira [26]3 years ago

4 0

X equals 18. This might not be correct

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#2 only <br> And it's to confusing

ipn [44]

They are easy to compare if they all have the same common denominator, then you can easily order them by the magnitude of the numerators...

85/10, -67/10, -56/10, 82/10 so now they are easy to compare...so

-6.7, -28/5, 8.2, 17/2

5 0

3 years ago

Find the sum of 1 + 3/2 + 9/4 + …, if it exists.

zmey [24]

Answer:

Option (4)

Step-by-step explanation:

Given sequence is,

$1+\frac{3}{2}+\frac{9}{4}..........$

We can rewrite this sequence as,

$1+\frac{3}{2}+(\frac{3}{2})^2.............$

There is a common ratio between the successive term and the previous term,

r = $\frac{\frac{3}{2}}{1}$

r = $\frac{3}{2}$

Therefore, it's a geometric sequence with infinite terms. In other words it's a geometric series.

Since sum of infinite geometric sequence is represented by the formula,

$S_{n}=\frac{a}{1-r}$ , when r < 1

where 'a' = first term of the sequence

r = common ratio

Since common ratio of the given infinite series is greater than 1 which makes the series divergent.

Therefore, sum of infinite terms of a series will be infinite Or the sum is not possible.

Option (4) will be the answer.

3 0

4 years ago

Need help using synthetic division!

viktelen [127]

Answer:

$3x^{2} -3x+8-\frac{9}{x+1}$

Step-by-step explanation:

Since we're dividing the polynomial by $(x+1)$ , we'll be using -1 to start the division.

Before setting the division up, let's list the coefficients of $x$ from descending powers and the constant.

The coefficient of $x^{3}$ is 3

Since we don't see an $x^{2}$ , the coefficient will be 0.

The coefficient of $x$ is 5.

Lastly, the constant, which is the term without the $x$ is -1.

Refer to the attached picture before continuing.

After referring to the picture, we now have the coefficients for the quotient.

The coefficient of $x^{2}$ is 3.

The coefficient of $x$ is -3.

The constant is 8.

Lastly, since the last number is not zero, it's the remainder just like regular division. This can be tricky to remember, but -9 is not the actual remainder.

The remainder is actually $\frac{-9}{x+1}$ .