Answer:
0.0903
Step-by-step explanation:
Given that :
The mean = 1450
The standard deviation = 220
sample mean = 1560
P(X> 1560) = P(Z > 0.5)
P(X> 1560) = 1 - P(Z < 0.5)
From the z tables;
P(X> 1560) = 1 - 0.6915
P(X> 1560) = 0.3085
Let consider the given number of weeks = 52
Mean = np = 52 × 0.3085 = 16.042
The standard deviation =
The standard deviation =
The standard deviation = 3.3306
Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.
Then;
Pr ( Y > 20) = P( z > 20)
From z tables
P(Y > 20) 0.0903
There are ways of drawing a 4-card hand, where
is the so-called binomial coefficient.
There are 13 different card values, of which we want the hand to represent 4 values, so there are ways of meeting this requirement.
For each card value, there are 4 choices of suit, of which we only pick 1, so there are ways of picking a card of any given value. We draw 4 cards from the deck, so there are possible hands in which each card has a different value.
Then there are total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is
one number that could round to 3 100 when rounded is 3 120
I think what you need to do is make B = -5
3a = -2(-5) - 7
3a = 10 - 7
3a = 3
a = 1
Area of the board divided by the time
2 x 3 = 6ft^2
15/6= 2.5mins