Question

Consider the two triangles. Triangles A B C and H G I are shown. Angles A C B and H I G are right angles. The length of side A C is 15 and the length of side C B is 20. The length of side H I is 12 and the length of I G is 9. To prove that the triangles are similar by the SAS similarity theorem, it needs to be shown that

Answer 1

Answer:

Both are similar by SAS similarity.

This SAS similarity is equivalent to the congruence.

Step-by-step explanation:

Step 1:

To prove that ACB and HIG as similar triangles.

We have to look upon the corresponding sides.

SAS= Side angle sides , there the angle must be in between two sides.

$\angle$ ACB = $\angle$ HIG

Lets work on the corresponding sides.

IG/AC = IH/AC

$\frac{9}{15}$ = $\frac{12}{20}$

Reducing each to lowest form, we divide numerator and denominator by 3 for the 1st fraction and by 4 for the 2nd fraction.

We have

$\frac{3}{5}$ = $\frac{3}{5}$

Both sides are equal.

So its proved that both are similar with SAS similarity theorem.

Answer 2

Answer: C

Step-by-step explanation: I worked it out for you :)