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4 years ago

Only find the range please thank you ^o^

Mathematics

2 answers:

fenix001 [56]4 years ago

8 0

Hoi!

To find the range of a data set, we must subtract the lowest numerical value from the highest. In this case, the highest value would be 3, and the lowest would be 0.

3 - 0 = 3

3 is your range. :)

Vesna [10]4 years ago

7 0

To find the range, subtract the smallest number by the largest, or 3 minus 0, which would be 3. The range is 3. Hope this helps!

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A large group of students took a test in Physics and the final grades have a mean of 70 and a standard deviation of 10. If we ca

Sholpan [36]

Answer:

The scores are between 50 and 90

Step-by-step explanation:

When we say middle 95%, we means that this value falls between 2 standard deviations of the mean i.e

μ ± 2σ

Hence,

mean of 70 and a standard deviation of 10

μ ± 2σ

μ - 2σ

70 - (2 × 10)

= 70 - 20

= 50

μ + 2σ

= 70 + (2 × 10)

= 70 + 20

= 90

4 0

3 years ago

Please help me out by answering these questions!

mel-nik [20]

A 3,-3

B 3,-6

C 7,-6

D 7, -3

6 0

3 years ago

Plz Help???

GREYUIT [131]

1.
12 liters of 26% acid solution contain $26\% \times 12=0.26 \times 12=3.12$ liters of acid.
x liters of 40% acid solution contain $40\%x=0.4x$ liters of acid.
The third solution is made from the two mixed solution so its volume is $12+x$ , and the volume of acid in it is $0.4x+3.12$ . Its concentration is 33% or 0.33.
The concentration of a solution is the volume of the solution divide by the volume of acid in it.

$\frac{0.4x+3.12}{12+x}=0.33 \\ 0.4x+3.12=0.33(12+x) \\ 0.4x+3.12=3.96+0.33x \\
0.07x=0.84 \\
x=12$

The answer is B.

2.
12 liters of 16% acid solution contain $16\% \times 12=0.16 \times 12=1.92$ liters of acid.
x liters of 40% acid solution contain $40\%x=0.4x$ liters of acid.
The volume of the third solution is $12+x$ , and the volume of acid in it is $0.4x+1.92$ . Its concentration is 32% or 0.32.

$\frac{0.4x+1.92}{12+x}=0.32 \\
0.4x+1.92=0.32(12+x) \\
0.4x+1.92=3.84+0.32x \\
0.08x=1.92 \\
x=24$

The answer is B.

3.
16 liters of 18% acidsolution contain $18\% \times 16=0.18 \times 16=2.88$ liters of acid.
x liters of 27% acid solution contain $27\%x=0.27x$ liters of acid.
The volume of the third solution is $16+x$ , and the volume of acid in it is $0.27x+2.88$ . Its concentration is 21% or 0.21.

$\frac{0.27x+2.88}{16+x}=0.21 \\
0.27x+2.88=0.21(16+x) \\
0.27x+2.88=3.36+0.21x \\
0.06x=0.48 \\
x=8$

The answer is A.

5 0

4 years ago

Use the distributive property to expand the expression.<br><br> -2(1/3x - 1/5)

Anna11 [10]

-2(1/3x - 1/5) = -2/3x + 2/5 --------------using <span>distributive property</span>

6 0

3 years ago

Read 2 more answers

6.4 How Many in 2?

FromTheMoon [43]

Answer:

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