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Natali5045456 [20]
3 years ago
5

Plz Help???

Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0
1.
12 liters of 26% acid solution contain 26\% \times 12=0.26 \times 12=3.12 liters of acid.
x liters of 40% acid solution contain 40\%x=0.4x liters of acid.
The third solution is made from the two mixed solution so its volume is 12+x, and the volume of acid in it is 0.4x+3.12. Its concentration is 33% or 0.33.
The concentration of a solution is the volume of the solution divide by the volume of acid in it.

\frac{0.4x+3.12}{12+x}=0.33 \\ 0.4x+3.12=0.33(12+x) \\ 0.4x+3.12=3.96+0.33x \\
0.07x=0.84 \\
x=12

The answer is B.

2.
12 liters of 16% acid solution contain 16\% \times 12=0.16 \times 12=1.92 liters of acid.
x liters of 40% acid solution contain 40\%x=0.4x liters of acid.
The volume of the third solution is 12+x, and the volume of acid in it is 0.4x+1.92. Its concentration is 32% or 0.32.

\frac{0.4x+1.92}{12+x}=0.32 \\
0.4x+1.92=0.32(12+x) \\
0.4x+1.92=3.84+0.32x \\
0.08x=1.92 \\
x=24

The answer is B.

3.
16 liters of 18% acidsolution contain 18\% \times 16=0.18 \times 16=2.88 liters of acid.
x liters of 27% acid solution contain 27\%x=0.27x liters of acid.
The volume of the third solution is 16+x, and the volume of acid in it is 0.27x+2.88. Its concentration is 21% or 0.21.

\frac{0.27x+2.88}{16+x}=0.21 \\
0.27x+2.88=0.21(16+x) \\
0.27x+2.88=3.36+0.21x \\
0.06x=0.48 \\
x=8

The answer is A.

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