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Tatiana [17]
3 years ago
12

6.4 How Many in 2?

Mathematics
1 answer:
FromTheMoon [43]3 years ago
4 0

Answer:

i dont understand the question

Step-by-step explanation:

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Simplify by combining like terms on each side of the equation. State your new equation.
vladimir1956 [14]

6x + x + x - 5 - 2 = 8 + 2x + x

combine like terms

8x -7 = 8 +3x

subtract 3x from each side

5x -7 = 8

add 7 to each side

5x = 15

divide by 5

x=3

Answer: 8x -7 = 8 +3x

x=3

6 0
3 years ago
what is the volume of the prism given that each cube is defined by the fractional edge length of 1/3 inch
Diano4ka-milaya [45]
The equation for volume is length times width times height. So to solve this multiple 1/3x1/3x1/3 because 1/3 is the length, width , and height of the cube(cubes have equal sides). The answer should be 1/27 
3 0
3 years ago
What integers fall between the square root of 12
Dafna1 [17]
The square root of 12 is 3.4.
Your integers are 3 and 4.
I hope this helps!
7 0
4 years ago
3 a. It takes Adriana 20 minutes to walk 5 blocks to the library. Complete the table of equivalent ratios to show Adriana’s two
Dafna11 [192]

Answer:

It takes 4 minutes per block and she can walk 12.5 blocks in 45 minutes.

Step-by-step explanation:

20 / 5 = 4 minutes per block

20 + 20 + 5 = 45

5 + 5 + 2.5 = 12.5

Hope this helps, I did the test last year.

6 0
3 years ago
Given that f(a+b)= f(a) + f(b) and f(x) is always positive, what os the value of f(0)?
FrozenT [24]
This is a strange question, and f(x) may not even exist. Why do I say that? Well..

[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).

[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!

Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.

To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
4 0
4 years ago
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